Problem 2- 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p = 773.3 kg/m2 60 m oil p = 899.6 kg/m 10 m water p 979 kg/m glycerin p 1236 kg/m 5 m 5 m
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Q: From the figure, which fluid will give a pressure of 700KPA? A- 90 kPa ethyl alcohol p- 773.3 kg/m…
A: to find - fluid which will give pressure of 700Kpa
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Q: In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa…
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Q: Problem 2 - 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans:…
A: To find out the fluid which achieved 700 kPa of pressure.
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Q: n Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po 90 kPa…
A: Draw the figure.
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- A glass 12 cm tall filled with water is invert the pressure at the closed end? Barometric pressure is 101.325 kPa. What is Ans. 100.15 kPaa Problem 2- 51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Proble Po 90 kPa A diffe water ethyl alcohol p= 773.3 kg/m³ mm, 1 betwe 60 m ol p= 899.6 kg/m 10 m water P= 979 kg/m' glycerin p = 1236 kg/m 5 m 5 m 2021/04/16 18:27Problem #4 If the pressure difference between points 1 and 2 is 25 psi, what will be the flow rate? The pipes are galvanized iron with 0.0005 ft. Take v = 1.06 × 10−5 ft²/s and neglect Kis = minor losses. 10 in. dia 1. 2000 ft, 8 in. dia A B 1600 ft, 6 in. dia с 2. 800 ft, 10 in. dia-A steady push on the piston in a syringe is shown in the figure causes a flow rate of 0.4 ml/sec. The fluid has a mass density of 900 kg/cum and an absolute viscosity of 0.002 Pa-sec. Assume that there is no headloss in the larger cylinder. Determine the reynolds number for the given flow of 0.4 ml/sec in he needle. 645 917 897 795 Determine the headloss in the needle 18.90 m 15.21 m 14.43 m 16.23 m Determine the force required to maintain the flow 64.23 kn 45.25 kn 34.77 kn 25.36 kn
- The tank contains a liquid having a density of 2.52 slugs/ft^3 10 in 5 ft 10 ft. 7 ft Pliquid 2. 52 slugs/ſt³ %3D a. Determine the unit weight of the liquid when it reaches the indicated level. b. Determine the liquid's weight. Use English units to express your response. c. Assuming no mixing of liquids occur, if glycerin (SG = 1.26) is poured into the tank, will it sink to the bottom, or will it float on the surface of the liquid, or will it be suspended in the liquid?Problem 2 -50 A glass 12 cm tall filled with water is inverted. The bottom is open. What is pressure at the closed end? Barometric pressure is 101.325 kPa. the Ans: 100.15 kPaa Problem 2 -51 In Figure 13, in which fluid will a pressure of 700 kPa first be achieved? Ans: glycerin Po = 90 kPa ethyl alcohol p= 773.3 kg/m 60 m oil p= 899.6 kg/m? 10 m water p = 979 kg/m glycerin p = 1236 kg/m 5 m 5 m8.11 It takes a certain length of time for the liquid level in a tank of diameter D to drop from position h, to position h, as the tank is being drained through an orifice of diameter d at the bottom. Determine the n- groups that apply to this problem. Assume that the liquid is nonviscous. Express your answer in the functional form. Ah = 13) f(T1, T2, d h2 Problem 8.11
- 4- Consider the system shown in the figure. If a change of P kPa in the pressure of air causes the brine- mercury interface in the right column to drop by d mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of A₂/A₁. P (kPa) d (mm) 6 Sum of last 2 digits of 35 YorkU ID# ending with 0, 2, 4, 6, 8 Sum of last 2 digits of 45 YorkU ID# ending with 1, 3,5,7,9 7 Area, A₁. Air Water Mercury SG = 13.56 Brine pipe SG = 1.1 Area, A₂Consider the problem of draining a hemispherical tank of radius H* feet that is full of water and has a circular drain hole of radius 3 inches at the bottom. How long will it take for the tank to empty? dv When the change volume is = -kA/2gh(t) A is the constant cross sectional area of the opening; and k is a constant determined by the viscosity of the fluid dh dt H H-h dV 1 dt dt ar² Note: Draining a hemispherical tank. Take H* as a last two digits of your ICEM ID, if last two digits less than 10 take H= 18 feet2. If the atmospheric pressure is 101.33 kPa and the absolute pressure at the bottom of the tank as shown in the figure is 215 kPa. a.) What is the specific gravity of olive oil? b. ) What is the absolute pressure at the interface of the olive oil and the mercury c.) What is the pressure at the bottom of the tank Sea Oil (sg-0.89) Water Olive oil Mercury (sg= 13.6) 1.5 m 2.5 m 3.0m 0.5 m
- Q2: A pressure gage 19.0 ft above the bottom of a tank containing a liquid reads 13.19 psi,another gage at height 14 .0 ft reads 15.12 psi. The density of * :the liquid is 1. 73 slug/ft O 3.10 slug/ft O 0.0216 slug/ft O 4.83 slug/ft OQuestion 8 Gasoline flows from one tank to the other as shown in the figure. The pipe is 25 mm with friction factor of 0.022. The second tank is vented. Given: h1 = 1.5 m h2 = 4.9 m h3 = 1.1 m x1 = 15.8 m x2 = 3.3 m hi h₂ P=? question will save this response. Gasoline X₁ Pipe H Xz Calculate the pressure (kPa) above the gasoline in the first tank that will result in a flowrate of 400 Liters/min. Express your answer in whole number. Vent D KA pressure in a given tank reads 265 mm of Hg. Determine the equivalentheight of a certain fluid in m with sp. gr = 3.44.