Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Transcribed Image Text:Problem #4
If the pressure difference between points 1 and 2 is 25 psi, what
will be the flow rate? The pipes are galvanized iron with
0.0005 ft. Take v =
1.06 × 10−5 ft²/s and neglect
Kis
=
minor losses.
10 in. dia
1.
2000 ft, 8 in. dia
A
B
1600 ft, 6 in. dia
с
2.
800 ft, 10 in. dia-
Transcribed Image Text:Step 1: Determine the given variable
Given:
Pressure difference between points 1 and 2 is 25 psi
Ks =0.0005 ft
v=1.06*10-5ft²/s
Step 2: Calculate the mass flow rate
Friction losses:
10.68L
*Q1.852
C1.852D4.87
losses reamins the same in parallel pipes
(hp) A = (h₂) B
h₂
=
10.68L A
C1.852 + |
*DA
remove the common things
2000*12 1.852=
*QA
84.87
4.87
1.852=
QA
*QA
1600*12
64.87
0.959*Q₁1.852= 3.116*Qg1.852
1.852=
1.852
3.116
0.959
Q1.852=3.249*Q¹1.8
*QB
10.68L B
1.852 4.87
'DB
1.852
.*QB
1.852
mass flow rate remains constant
Q₁ = QA+QB = Qc = Q₂
1.852
Applying bernoullis equation between 1 and 2
P₂ V₂²
pg
P₁ v₁²
+ +2₁=
pg
2g
Z₁ = 2₂
V₁ = V₂
Q₁ = Q₂
P₁-P₂
pg
= (h₂)₂ + (1₂) g + (h₂) c
25*6894.757*39.37
1000*9.81
691.759 =
2g
- +2₂+(1₂) ₁-2
10.68LA
C1.852 DA
10.68 2000*12*3.25 Qg¹
C1.852
84.87
691.759 *1291.852=3.119 Qg"
10.68
QB-73373.209 1.852
Q=423.818 in ³/sec
flow rate:
QA+Q8=2.89 QB
4.87
=
1.852 +3.116 Q
Q1.852
1.852
1.852
525044.0109-Q1.852 (3.119+3.116+0.9208)
525044.0109
(3.119+3.116+0.9208)
Q1.852=73373.209
flow rate=2.89*423.818 (0.000578)
flow rate=0.707 cfs.
10.68Lc
C1.852 DC
1600*12*Q1.852 800*12*(Q+Q)1.852
64.87
104.87
10.68L B
C1.852 D
4.87
1.852+
"QB
1.852 +0.129 (1.89+1)1.852 Qg¹.
1.852
4.87
*Qc
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- Please fast only final answer neededarrow_forwardAnswer fastarrow_forwardA pipe connected in series has the following roughness or friction coefficients: Pipe 1 C = 80 (Hazen-Williams) Pipe 2 n = 0.015 (Chezy-Manning) Pipe 3 f = 0.025 (Darcy-Weisbach) All pipes have a diameter of 400mm, length of 1 kilometer, and flow rate of 150 L/s. Determine the headloss on Pipe 1 in meters.arrow_forward
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