Problem #1: Write an LC-3 ML program to perform the following operations in sequence. Assume that memory address x3010 contains some non-zero integer value. 1. Add +10 to the contents of address x3010 it is odd, and subtract 10 if it is even. 2. If the result is negative, store a -1 in address x3011. Load your program starting at address x3000. Problem #2: Write an LC-3 ML program to perform the following logic: if (M[x3200] > M[x3201]{ M[x3202] = M[x3200] - M[x3201] M[x3201] = M[x3202] * 2 } else { M[x3202] = M[x3201] - M[x3200] M[x3201] = M[x3202] + 10 } Load your program starting at address x3100. You will need to demonstrate the correct execution of your instructions by using the LC-3 Simulator. Make sure you upload your program into Canvas by the deadline.
Problem #1: Write an LC-3 ML program to perform the following operations in sequence. Assume that memory address x3010 contains some non-zero integer value. 1. Add +10 to the contents of address x3010 it is odd, and subtract 10 if it is even. 2. If the result is negative, store a -1 in address x3011. Load your program starting at address x3000. Problem #2: Write an LC-3 ML program to perform the following logic: if (M[x3200] > M[x3201]{ M[x3202] = M[x3200] - M[x3201] M[x3201] = M[x3202] * 2 } else { M[x3202] = M[x3201] - M[x3200] M[x3201] = M[x3202] + 10 } Load your program starting at address x3100. You will need to demonstrate the correct execution of your instructions by using the LC-3 Simulator. Make sure you upload your program into Canvas by the deadline.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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For example, instruction like this.
0011 0000 0000 0000 ; start at x3000
0001 001 001 1 00000 ;x3000 set N CC if R1 < 0
0000 100 0 0000 0001 ;x3001 if N goto x3003 R2+=5
0000 111 0 0000 0001 ;x3002 Not N goto x3004
0001 010 010 1 00101 ;x3003 R2 += 5
;x3004 done
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