Problem 1: A reverse curse connects two converging tangents intersecting at an angle of 30°. The distance of the intersection from the P.I. of the curve is 160 meters. The deflection angle of the common tangent from the back tangent is 20°R, and the azimuth of the common tangent is 320°. The degree of the second simple curve is 6° and the stationing of the point of intersection of the first curve is 4 + 450. Determine the stationing of the P.C. and P.R.C. and the P.T.
Problem 1: A reverse curse connects two converging tangents intersecting at an angle of 30°. The distance of the intersection from the P.I. of the curve is 160 meters. The deflection angle of the common tangent from the back tangent is 20°R, and the azimuth of the common tangent is 320°. The degree of the second simple curve is 6° and the stationing of the point of intersection of the first curve is 4 + 450. Determine the stationing of the P.C. and P.R.C. and the P.T.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Problem 1: A reverse curse connects two converging tangents
intersecting at an angle of 30°. The distance of the intersection from the
P.I. of the curve is 160 meters. The deflection angle of the common
tangent from the back tangent is 20°R, and the azimuth of the common
tangent is 320°. The degree of the second simple curve is 6° and the
stationing of the point of intersection of the first curve is 4 + 450.
Determine the stationing of the P.C. and P.R.C. and the P.T.
Transcribed Image Text:ア.C.
4+ 450円
RZ
20
P.R.S.
1に 20°
50
30
P.Tロ
B.
C
160m
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