Problem 01: For the following parallel network, the supply voltage E = 200VZ30° with 250 rad/s as shown inFigure 01:R2R3R4EL, X= 36 2L3 X12X1A L4CキXaXc4 = 40 2 CFigure 01ie voltage drop (in polar form) across the resistance R1 =

In this question we will find voltage drop across R1 in polar form...

Problem 01: For the following parallel network, the supply voltage E = 200VZ30° with 250 rad/s as shown Figure 01: R2 R3 R4 E L, X= 36 2 L3 X12 %3D XC4= 40 2F Figure 01 ie voltage drop (in polar form) across the resistance R1 %3D

Problem 01: For the following parallel network, the supply voltage E = 200VZ30° with 250 rad/s as shown Figure 01: R2 R3 R4 E L, X= 36 2 L3 X12 %3D XC4= 40 2F Figure 01 ie voltage drop (in polar form) across the resistance R1 %3D

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter8: Symmetrical Components

Section: Chapter Questions

Problem 8.1P

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Question

Problem 01: For the following parallel network, the supply voltage E = 200VZ30° with 250 rad/s as shown in
Figure 01:
R2
R3
R4
E
L, X= 36 2
L3 X12
X1A L4
CキXa
Xc4 = 40 2 C
Figure 01
ie voltage drop (in polar form) across the resistance R1 =

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