PrimaryEL 600 VoltsEP =IL||||IP =PrimarySecondarySecondaryEL =EP = 277 VoltsIL =IP =Ratio =VA 125 KVA=1. What size THW copper conductors are needed for the primary conductors?2. What size THW copper conductors are needed for the secondary conductors?3. What size Overcurrent protection is needed for the primary conductors?

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Answered: Primary EL 600 Volts EP = IL |||| IP =…

Engineering

Electrical Engineering

Primary EL 600 Volts EP = IL |||| IP = Ratio = Primary Y Secondary Secondary EL = EP = 277 Volts IL = IP = VA = 125 KVA

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter20: Special-purpose Outlets For Ranges, Counter-mounted Cooking Unit , And Wall-mounted Oven

Section20.1: Counter-mounted Cooking Unit Circuit

Problem 4R

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

Primary
EL 600 Volts
EP =
IL
||||
IP =
Primary
Secondary
Secondary
EL =
EP = 277 Volts
IL =
IP =
Ratio =
VA 125 KVA
=
1. What size THW copper conductors are needed for the primary conductors?
2. What size THW copper conductors are needed for the secondary conductors?
3. What size Overcurrent protection is needed for the primary conductors?

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