Precisely specify the conditions under which the following algorithm returns true, and then discuss, in detail, the running time of the algorithm. If you think it has different best- and worst-case running times then these should be considered separately, and you should explain the conditions under which best and worst cases arise. explain your answer and use O, Ω and ø Algorithm Ex1 ((?1, ... ??), (?1, ... , ??)) ?←0 for ? ← 1 to ? do               ?←1               while ? ≤ ? do                            If ?? ==??                                     ?←?+1                              ?←?+1 return ? > 0

Not an exam. Just review for me. For each function f(n) below give an asymptoic upper bound using big-Oh notation. You should give the tighest bound (ie. smallest bound) possible and simplify the expression.  Explain step by step how you your answers. Use signma notation to prove your answers if you can     I attached the answers for question 3 and 4 for your reference so you can check your work but explain how you got those answers.  I dont have the answer key for 1 so please try your best on that.

Another recursive algorithm is applied to some data A = (a₁, ..., am) where m = 2* (i.e. 2, 4, 8,16 ...) where x is an integer ≥ 1. The running time T is characterised using the following recurrence equations: T(1) = c when the size of A is 1 T(m) = 2T (2) + c otherwise Determine the running time complexity of this algorithm.

In each of the problems below compute the average case time complexity (or expected time) of the given code. State your answer using asymptotic notation. Show your work for this problem by stating what the different cases are, the probability of each case, and how long each case takes. Also show the calculation of the expected time. a) def foo (n): #randomly choose a number between 0 and n-1 in constant time k np.random.randint (n) if k np. sqrt (n): for i in range(n): print (i) print('Never mind...') else: b) def bogosearch (numbers, target): """search by randomly guessing. numbers is an array of n numbers""" n = len (numbers) while True: #randomly choose a number between 0 and n-1 in constant time guess = np.random.randint (n) if numbers [guess] == target: return guess In this part, you may assume that the numbers are distinct and that the target is in the array. Hint: if 0 < b < 1, then 1p.bp-1 (1-b)². =