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Practice Problem 27-5 Determine the energy released when a 235U nucleus under- goes fission to 134Te, "Zr, and two neutrons. A table of isotopes lists the binding energy per nucleon in the nuclei of 235U, 134Te, and 9Zr as 7.59 MeV, 8.38 MeV, and 8.54 MeV, respectively.

Practice Problem 27-5 Determine the energy released when a 235U nucleus under- goes fission to 134Te, "Zr, and two neutrons. A table of isotopes lists the binding energy per nucleon in the nuclei of 235U, 134Te, and 9Zr as 7.59 MeV, 8.38 MeV, and 8.54 MeV, respectively.

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Practice Problem 27-5: **Determine the energy released when a \(^{235}U\) nucleus undergoes fission to \(^{134}Te\), \(^{99}Zr\), and two neutrons. A table of isotopes lists the binding energy per nucleon in the nuclei of \(^{235}U\), \(^{134}Te\), and \(^{99}Zr\) as 7.59 MeV, 8.38 MeV, and 8.54 MeV, respectively. **Explanation:** In this problem, we are looking to find the energy released during the fission process of a \(^{235}U\) nucleus. To do this, we will utilize the provided binding energies per nucleon for the nuclei involved: \(^{235}U\), \(^{134}Te\), and \(^{99}Zr\). First, we will calculate the total binding energy for each nucleus by multiplying the binding energy per nucleon by the total number of nucleons (mass number) in the respective nucleus. Once obtained, we can determine the difference in the total binding energy before and after the fission process to find the energy released. **Binding Energies:** - \(^{235}U\) (Uranium-235): 7.59 MeV per nucleon - \(^{134}Te\) (Tellurium-134): 8.38 MeV per nucleon - \(^{99}Zr\) (Zirconium-99): 8.54 MeV per nucleon This fission process helps illustrate key concepts in nuclear physics related to the stability of nuclei and the release of nuclear energy.
Transcribed Image Text:**Practice Problem 27-5: **Determine the energy released when a \(^{235}U\) nucleus undergoes fission to \(^{134}Te\), \(^{99}Zr\), and two neutrons. A table of isotopes lists the binding energy per nucleon in the nuclei of \(^{235}U\), \(^{134}Te\), and \(^{99}Zr\) as 7.59 MeV, 8.38 MeV, and 8.54 MeV, respectively. **Explanation:** In this problem, we are looking to find the energy released during the fission process of a \(^{235}U\) nucleus. To do this, we will utilize the provided binding energies per nucleon for the nuclei involved: \(^{235}U\), \(^{134}Te\), and \(^{99}Zr\). First, we will calculate the total binding energy for each nucleus by multiplying the binding energy per nucleon by the total number of nucleons (mass number) in the respective nucleus. Once obtained, we can determine the difference in the total binding energy before and after the fission process to find the energy released. **Binding Energies:** - \(^{235}U\) (Uranium-235): 7.59 MeV per nucleon - \(^{134}Te\) (Tellurium-134): 8.38 MeV per nucleon - \(^{99}Zr\) (Zirconium-99): 8.54 MeV per nucleon This fission process helps illustrate key concepts in nuclear physics related to the stability of nuclei and the release of nuclear energy.
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