Positive point charges g = 9.00 µC and q' = 2.00 µC are moving relative to an observer at point P, as shown in the figure (Figure 1). The distance d is 0.130 m. v = 4.60x10° m/s. and = 9.20x10° m/s.

Consider an electron that is 1.5·10−10 m from an alpha particle with charge 3.2·10−19 C. (a) What is the electric field due to the alpha particle at the location of the electron? The direction of the electric field by the alpha particle at the electron is

In Rutherford's famous scattering experiments that led to the planetary model of the atom, alpha particles (having charges of +2e and masses of 6.64 x 10-27 kg) were fired toward a gold nucleus with charge +79e. An alpha particle, initially very far from the gold nucleus, is fired at 2.76 x 107 m/s directly toward the nucleus, as in the figure below. How close does the alpha particle get to the gold nucleus before turning around? Assume the gold nucleus remains stationary. 79e m v=0

The electric field in a region is uniform (not changing over distance) with a magnitude of 1.62 x10^3 N/C and it points in the +x direction.  What is the magnitude of the voltage difference between two points separated on the x‐axis by a distance of 2.50 mm?