Please use MapReduce to solve this problem. Some important points you must clarify: 1. How to separate data? 2. What is the Map task? What's the format of pairs? 3. What is the Reduce task? How do we get the final results?

Create an Ordered Doubly Linked List in C++. Remember that an ordered Linked List is one where inserts automatically place a new node so that all the nodes retain a certain order. This list should be templated where items should be in "ascending" order (i.e., if it is a list of numbers, it should be of order of least to greatest).

CREATE DATABASE COUNTRIES; USE COUNTRIES; DROP TABLE IF EXISTS `City`; CREATE TABLE `City` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Name` char(35) NOT NULL DEFAULT '', `CountryCode` char(3) NOT NULL DEFAULT '', `District` char(20) NOT NULL DEFAULT '', `Population` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`) ) ENGINE=MyISAM AUTO_INCREMENT=4080 DEFAULT CHARSET=latin1; -- -- Dumping data for table `City` -- -- ORDER BY: `ID` INSERT INTO `City` VALUES (1,'Kabul','AFG','Kabol',1780000); INSERT INTO `City` VALUES (2,'Qandahar','AFG','Qandahar',237500); INSERT INTO `City` VALUES (3,'Herat','AFG','Herat',186800); INSERT INTO `City` VALUES (4,'Mazar-e-Sharif','AFG','Balkh',127800); INSERT INTO `City` VALUES (5,'Amsterdam','NLD','Noord-Holland',731200); INSERT INTO `City` VALUES (6,'Rotterdam','NLD','Zuid-Holland',593321); INSERT INTO `City` VALUES (7,'Haag','NLD','Zuid-Holland',440900); INSERT INTO `City` VALUES (3068,'Berlin','DEU','Berliini',3386667); INSERT INTO `City` VALUES…

java Draw a picture of the HashSet created by the data shown below. Assume the HashSet (1) has an initial size of 11, (2) uses separate chaining, and (3) inserts new nodes at the start (not end) of the chain. -4, 2, 18, 23, -15, 47, 87, 2032, 5393, 2, 53432

Suppose you generate the following RSA key pairs: •p = 37199 •q = 49031 •N = p•q = 1823904169 • (p - 1) · (q - 1) = 1823817940 •e = 65537 (for encryption) •d = 1578812933 (for decrption) Assuming a=01, b=02, ..., z=26, and we group the digits in groups of three. (ii) If you receive strings of digits from a sender: 199770170, 1288754980, 324346846, 1370682962, decrypt the message.

The dotted-decimal notation for the IP address 10010000 10101010 01011011 00101000 The dotted-decimal notation for the IP address 10000001 10100101 01010011 00110011 ​2 15​ 19​ 30​ 41​ 59​ 77​ 81​ 85​ 100​   Search for element 45 in the list above using a binary search algorithm. Clearly, show the first, middle, and last indexes as well as the target in every iteration. Show all the steps taken. Use the table below as a guideline with the provided format.   Instructions: Start your index at 0 Show all steps Mark the first row as header(The text will be in bold). Use the index number to show the first, last, and mid Use the floor function to find the middle element If struggling to insert a table, you may work this from a Word document and upload your work using the plus sign on the editing options.   ​First last​ mid​ 0​ 1​ 2​ 3​ 4​ 5​ 6​ 7​ 8​ 9​ target​ = 45

In a 384-well plate luciferase assay, we drugged 4 receptors (A, B, C, D) with their endogenous agonists at a range of doses. Below is a subset of the resulting data frame (please use the full data frame attached to the original email as a CSV file). Each row of this data frame corresponds to a single well of the 384 well plate. The columns are as follows: receptor: the receptor tested in the well agonist: the endogenous agonist used for a receptor agonist_nM: the dose of the endogenous compound (in nanomolar) ● RLU: raw luminescence of the well (our measure of receptor activity) To answer this 3 part question, we’ll ask you to submit a PDF file containing all of your source code, plots, and written interpretation. (Using something like a Jupyter Notebook with Python or Rmarkdown is recommended, but not required.) You should provide brief explanations of your thought process at each step. Part A: Different receptors have different basal rates of activity. To better facilitate…

We have a poorly-designed hash map where all of the stored values are in one bucket (meaning they're all in one Linked List). Explain why this undermines the advantages of a hash map.