PYTHON/JUPYTER NOTEBOOKS  Given the reaction sustem : *NO3^2- + H^+ <-> *NO2 + OH^- e^- + NO3^- <-> *NO3^2- *NO3^2- + H^+ <-> HNO3 + e^- *NO3^2- + *OH <-> NO3^- + OH^- *NO3^2- + O2 <-> NO3^- + O2^- N2O4 + H2O <-> NO3^- + NO2^- + 2 H^+ *NO2 + *OH <-> NO3^- + H^+ *NO2 + H* <-> HNO2 *NO2 + HO2* <-> O2NO2H O2NO2H <-> O2NO2^- + H^+ O2NO2^- + H^+ <-> O2NO2H O2NO2^- + H^+ + 2 e^- <-> OH^- + NO3^- O2NO2H + e^- <-> *OH + NO3^- NO2^- + *OH <-> *NO2 + OH^- NO2^- + e^- <-> NO2^2- NO2^- + H2O + e^- <-> NO + 2 OH^- ONO2H + e^- <-> *NO2 + OH^- NO + e^- <-> NO^- NO + H* <-> NO^- + H^+ NO + *OH <-> NO2^- + H^+ NO + O2^- <-> ONO2^- NO + HO2* <-> ONO2H ONO2^- + e^- + H2O <-> *NO2 + 2 OH^- *NO2 + NO + H2O <-> 2 HNO2 1) Make an organized output of the species and stoichiometric data  (0,1,1,0...etc

PYTHON/JUPYTER NOTEBOOKS 

Given the reaction sustem :

*NO3^2- + H^+ <-> *NO2 + OH^-
e^- + NO3^- <-> *NO3^2-
*NO3^2- + H^+ <-> HNO3 + e^-
*NO3^2- + *OH <-> NO3^- + OH^-
*NO3^2- + O2 <-> NO3^- + O2^-
N2O4 + H2O <-> NO3^- + NO2^- + 2 H^+
*NO2 + *OH <-> NO3^- + H^+
*NO2 + H* <-> HNO2
*NO2 + HO2* <-> O2NO2H
O2NO2H <-> O2NO2^- + H^+
O2NO2^- + H^+ <-> O2NO2H
O2NO2^- + H^+ + 2 e^- <-> OH^- + NO3^-
O2NO2H + e^- <-> *OH + NO3^-
NO2^- + *OH <-> *NO2 + OH^-
NO2^- + e^- <-> NO2^2-
NO2^- + H2O + e^- <-> NO + 2 OH^-
ONO2H + e^- <-> *NO2 + OH^-
NO + e^- <-> NO^-
NO + H* <-> NO^- + H^+
NO + *OH <-> NO2^- + H^+
NO + O2^- <-> ONO2^-
NO + HO2* <-> ONO2H
ONO2^- + e^- + H2O <-> *NO2 + 2 OH^-
*NO2 + NO + H2O <-> 2 HNO2

1) Make an organized output of the species and stoichiometric data  (0,1,1,0...etc)

2)Compute the rank of the stoichiometric matrix using your own algorithm. Is the matrix full rank? Is mass conserved for the first 3 reactions and the last 3 reactions? Kindly Explain.