Please help correct part C) thanks
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A: Given: P(No response) = 0.04 P(short of expectations) = 0.26 P(met expectations) = 0.65
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A: Solution: Given information: k=5 Categories n=18+25+13+9+9= 74 Sample size
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A: "Since you have asked multiple question,we will solve the first question for you.If you want any…
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A: given data, n=21x¯=5149s=1777df=n-1=21-1=20A)CI=0.90α=1-0.90=0.10
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A: Assume that σ is the population standard deviation of the duration times of game play.
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A: CI=0.99n=1688X=84p^=xn=841688=0.0498CI=0.99α=1-0.99=0.01
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A: Given that: Success probability, p=0.90 Sample size, n=30
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A: given data, claim:p>0.24x=857n=3401α=0.05we have to complete hypothesis for the given data,
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A: a) OPTION B ) there is one critical value , the critical value is = 2.33 Rules :- if alternative…
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A: As per our guidelines we are suppose to answer only three sub parts. Given,sample…
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A: given data, n=50x¯=3.2s=17.5CI=0.95α=1-0.95=0.05
Q: Consider
A:
Q: Problem 2: Hypothesis Tests Use a t-distribution and the matched pair sample results d = -2.6, sd =…
A: Rules :- we have to construct null and alternative hypotheses as followswe know that null…
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A: P18 is representing 18th quantile.
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A: Here option D is correct. The plot below is an example of Normal Probability Distribution.
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A: Solution : Let y = price to x = screen size.
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A: GivenMean(x)=41standard deviation(σ)=11sample size(n)=34significance level(α)=0.01The null and…
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A: given data normal distribution μ= 100σ= 15 p(70<x<125) = ?
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A: Given: μ = 180 σ = 27 Formula Used: Z = X-μσ
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A: Given that the ratio random variable of two random variables X and Y is Z=XY.
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A: Solution: Given that, Estimate the proportion of students on her campus who eat cauliflower n=20 #…
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A:
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A: From the provided information, Population standard deviation (σ) = 12 Sample mean (x̄) = 122.5…
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A: From the provided information, Sample proportion of blue M&M (p̂) = 0.10 Confidence level = 90%…
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A: Given that, n= 13 and probability p= 0.35 X~ Binomial (13,0.35)
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A: Given,sample size(n)=16sample mean(x¯)=$35sample standard deviation(s)=$3
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A: The sample space of rolling a pair of dice is, Sample space…
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A:
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A: Given: n = 6 α = 0.01 Formula Used: r = n∑XY-∑X∑Yn∑X2-∑X2n∑Y2-∑Y2
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Q: what is c? count?
A: Here C stands for combinations. Combinations is represented as nCr = n!/(n-r)!r!
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A: Given: n = 6 Formula Used: Standard deviation s = ∑Xi-X2n-1
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A: given data standard normal distribution Z~N(0,1) P(x<Z) = 0.2061 Z = ?
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A drug is…
A: Givensample size(n)=4658x=105Cofidence level=95%
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A:
Q: Assume that a simple random sample has been selected from a normally distributed population and test…
A: Method: Reject H0. If P-value is less than the level of significance alpha
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A: By using the standard deviation to find the sampling error Formula used: Sampling error= sampling…
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A: Given: n = 100 α = 0.05 Formula Used: Test-χ2 = ∑O-E2E
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A: given data x¯ = 98.38s1 = 0.45n1 = 15x¯2 = 98.17s2 = 0.65n2 = 91α = 0.01
Q: Let X be a random variable with Normal distribution, mean = 16, sd = 2. Find the value of x such…
A: From the provided information, Mean (µ) = 16 Standard deviation (σ) = 2 X~N (16, 2)
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A: Given information: The manager of the Granite Rock Company believes that the average truckload…
Q: The following are 30 UAS scores for the UT Statistics Student PPD Course. 75 89 47 80 65 59 60 75 84…
A: The following information has been provided: 56 75 89 47 80 65 55 78 90 59…
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A: The given standard deviation is 121.7, significantly high is 1377.8.
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A: given data clim : p < 0.12n = 100x = 9α = 0.10p^ = xn = 9100 = 0.09
Q: Many high school students take the AP tests in different subject areas. In one year, of the 144,154…
A: From the provided information, n1=144154x1=84175n2=219591x2=127895α=0.05
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A:
Q: The test statistic of z=0.87 is obtained when testing the claim that p > 0.4. a. Identify the…
A: GivenTest statistic(z)=0.87claim is that p>0.4
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A:
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- Unfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 6.7 ppb arsenic, with s = 3.0 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. n USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Ho: H = 8 ppb; H,: u > 8 ppb O Ho: H = 8 ppb; H,: H + 8 ppb O Ho: H 8 ppb; H,: u = 8 ppb O Ho: H = 8 ppb; H,: µ 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.005 < P-value < 0.010 P-value < 0.005 Sketch the sampling distribution and show the area corresponding to the P-value. MacBook Pro escUnfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 7.1 ppb arsenic, with s = 2.2 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. A USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Họ: u = 8 ppb; H,: u > 8 ppb O Ho: H 8 ppb; H,: u = 8 ppb (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The standard normal, since the sample size is large and a is unknown. O The Student's t, since the sample size is large and a is known. O The standard normal, since the sample size is large and a is known. The Student's t, since the sample size is large and a is unknown. What is the…An article compared the dielectric constants between two types of asphalt, HL3 and HL8, commonly used in pavements. For 42 specimens of HL3 asphalt the average dielectric constant was 5.92 with a standard deviation of 0.15, and for 37 specimens of HL8 asphalt the average dielectric constant was 6.05 with a standard deviation of 0.16. Can you conclude that the mean dielectric constant differs between the two types of asphalt? Find the P-value and state a conclusion. The P-value is . Round the answer to four decimal places. We (Click to select) cannot can conclude that the mean dielectric constant differs between the two types of asphalt.
- Unfortunately, arsenic occurs naturally in some ground water.t A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 7.1 ppb arsenic, with s = 2.2 ppb. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use a = 0.01. A USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Ho: H= 8 ppb; H,: H > 8 ppb O Ho: H 8 ppb; H: H = 8 ppb (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. O The standard normal, since the sample size is large and a is unknown. O The Student's t, since the sample size is large and a is known. O The standard normal, since the sample size is large and a is known. O The Student's t, since the sample size is large and a is unknown. What is…To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 41 feet. Assume the population standard deviation is 4.6 feet.The mean braking distance for Make B is 42 feet. Assume the population standard deviation is 4.4 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e). (a) Identify the claim and state Ho and Ha. What is the claim? A.The mean braking distance is different for the two makes of automobiles. This is the correct answer. B.The mean braking distance is the same for the two makes of automobiles. C.The mean braking distance is less for Make A automobiles than Make B automobiles. Your answer is…To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.6 feet. The mean braking distance for Make B is 47 feet. Assume the population standard deviation is 4.2 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e).
- A biologist knows that the average length of a leaf of a certain plant is 4 inches. The standard deviation of the population is 0.6 inch. A sample of 20 leaves of that type of plant given a new type of plant food had an average length of 4.2 inches. At α = 0.01, is there reason to believe that the new food is responsible for a change in the growth of leaves?In a Ni-Cd battery, a fully charged cell is composed of nickelic hydroxide. Nickel is an element that has multiple oxidation states. Assume the following proportions of the states: Nickel Charge Proportions Found 0 0.17 +2 0.33 +3 0.33 +4 0.5-0.33 Determine the variance of the nickel charge. Please enter the answer to 3 decimal places.Find the critical values of Z for a two tail test at alpha a = 0.05 LOS. Click this link for Normal table: https://drive.google.com/drive/folders/10Vh9s usp=sharing а. 1.65 b. +1.96 С. 2.33 d. +2.58