College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Given:
The initial speed of the object is 0 m/s.
The height of the object from the ground is 68.4 m.
The time taken by the object to reach the ground is 5.49 s.
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- Superman throws a chocolate-covered peanut into the air and catches it in his mouth 6 seconds later. a) How fast did he throw the peanut? ______ b) What if Superman is on Planet Krypton, where g = 15 m/s2 ? ______ c) What if Superman is on the moon, where g is approximately -2 m/s2 ? ______arrow_forward9. A carnival attraction tests your strength by how far in the air you can drive a weight with a hammer. You are able to throw the hammer with a velocity of 31 ft/sec. The hammer starts at a position 2 feet off of the ground. a) How long is the hammer in the air? b) How high are you able to throw the hammer? c) How long does it take the hammer to reach that height? d) How high in the air is the hammer after 1 second?arrow_forwardFigure out the acceleration due to gravity ( g ) on various hypothetical alien planets. On planet #2, you launch a projectile straight up from the ground at a speed of 27.9 m/s. The projectile reaches a maximum height of 75.5 m before falling back to the ground. What is the value of g for planet #2?arrow_forward
- 5. An astronaut drops a hammer from 2.0 meters above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 meters per second, how long will it take for the hammer to fall to the Moon's surface? (1) 0.62 s (2) 1.2 s (3) 1.6 s (4) 2.5 s S (1arrow_forwardYou are on your way to the store but realized you forgot your car keys. You ask your friend to throw you the keys from the apartment complex. The window your friend throws it from is 10 meters above the ground, and he chucks them with a speed of 2m/s at an angle of 25 degrees above horizontal. Acceleration due to gravity near the surface of earth is 9.8m/s^2 1) How far from the window do you need to stand to catch the keys.arrow_forwardThe trap-jaw ant, found throughout tropical South America, catches its prey by very rapidly closing its mandibles around its victim. Shown is the speed of one of its mandible jaws versus time in microseconds. a. What is the maximum acceleration of the ant’s mandible? b. The mass of a trap-jaw ant’s mandible has been estimated to be about 1.3 x 10-7 kg. Estimate the maximum force exerted by one mandible.arrow_forward
- 1.A spacecraft starts from rest, and makes a journey to a destination 258000 km from its starting point. It does so by accelerating at a constant rate of 11.65 m/s^2 up to the midpoint of the journey, and then decelerates at the same constant rate of 11.65 m/s^2 for the second half of the journey, ending at rest. How long did the entire journey take? 2 hr 37 min 1 hr 51 min 6 hr 9 min 3 hr 5 min 2. An unidentified flying object (UFO) is observed to travel a total distance of 47000 m, starting and ending at rest, over a duration of 1.18 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2. 6,882 g s 135,019 g s 67,509 g s 13,763 g s 3. A Ford passes a Toyota on the road (both vehicles are traveling in the same direction). The…arrow_forwardNo answer text proVided.. You selected this answer. Question 1 0 / 0.4 pts The figure shows an object moving at constant speed in a circular path. What is the velocity of the object at the indicated point? O 0 = v(- cos(0)î + sin(0)ĵ) O i = v(- sin(@)î + cos(8)ĵ) O ū = v(- sin(0)î – cos(0)ĵ) ü = v(sin(0)î + cos(0)Î) O i = v(cos(0)î + sin(0)ĵ)arrow_forwardYou start out by driving 82 miles north in 4 hours and 36 minutes, and then you stop and park for a while. Finally you drive another 60 miles south in 3 hours and 11 minutes. The average velocity for your entire trip was 2.26 miles per hour to the north. How much time did you spend parked?1 hour 56 minutes 3 hours 53 minutes 0 hours 58 minutes 9 hours 43 minuarrow_forward
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