Percent Yield C7H6O3 salicylic acid + CHO acetic anhydride C9H8O4 + Aspirin CH3COOH acetic acid 10.00 kg of salicylic acid is mixed with 10.00 kg of acetic anhydride. What is the % yield for aspirin if 11.2 kg is produced?
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- A student crystallizes 1.8 g of benzoic acid and isolate 0.5 g as the first crop. What is the percent recovery in this first crop?Mass of oleic acid (glyceryl trioleate)=3.978g Mass of soap (sodium oleate)=3.8954g Moles of Oleic Acid (glyceryl trioleate) 3.978g/(885.4g/ml)=0.004493mol Moles of Soap (sodium oleate) 3.8954g/(304.4g/ml)=0.01279 What is the theoretical yield? What is the yield percentage? of the one with less molarityMolar Mass (g/mole) Density (g/mL) Equivalent (ratio) Reagent Salicylic acid Amount Mole 138.12 Acetic anhydride 102.1 1.08 Sulfuric acid 98 1.8 catalyst
- ou separated acetanlide from sand and sodium chloride (NaCl) via recrystallization. You separated the recrystallized acetanilide from the dissolved NaCl using a seperatory funnel. You started the separation experiment with 4 g of an impure mixture of NaCl, sand, and acetanilide (MW= 135.17 g/mol) and you collected 3.2 g after the recrystallization experiment.Whats the percent yield?A side reaction of the rayon manufacturing process from wood pulp is: 3CS2 +6NaOH=2Na2CS3 +Na2CO3 +3H2O How many grams of Na2CS3 are produced in the reaction of 92.5ml of liquid Cs2 (d: 1.26g/ml) and 2.78mol of NaOH? How much excess reagent is left? How much would it take for the limiting reagent to react with the excess reagent?2.9g of beta-napthol and 1.65g of KOH were dissolved in 20ml of methanol with 1.8 ml of etl in a 50ml in round bottom flask and reacted to form 0.47 g of nerolin. What is the theoretical, actual and percent yield?
- For the preparation of Aspirin calculate limiting factor, theoretical yield calculations, percent yield calculations for salicylic acid used 8.6g, Acetic anhydride used 3.9ml, Phosphoric acid used 0.25ml and Acetyl salicylic acid obtained 7.2g1. A buffer is prepared using lactic acid (HLac) and sodium lactate (NaLac). 0.300 dm3 of the 0.500 mol·dm–3 HLac solution is mixed with 0.300 dm3 of the 0.300 mol·dm–3 NaLac solution to prepare the buffer. Ka for lactic acid (HLac) is 1.4 x 10-4 What will the pH of the above solution be after 5.0 cm3 of 0.200 mol·dm–3 NaOH has been added to only 100.0 cm3 of this buffer? 2. Data in the table below were collected at 25°C for the following reaction:2 I–(aq) + S2O82–(aq) I2 (aq) + 2 SO42-(aq) a) Determine the rate law for the reaction. b) Calculate the rate constant, giving the correct units for k.What is the percent magnesium hydroxide, if a sample of magnesia magma weighing 5.2430g when dissolved in 25 mL of 0.9915 N H2SO4 required 9.85 mL of 1.4102 N NaOH to titrate the excess acid? Round to 2 decimal point; Answer should be with the correct unit.
- A commercial vinegar is analyzed for the percent acetic acid present. The data for the first trial is given below. Calculate the required quantities using the raw data below. Preparation of Vinegar Sample: • Mass of vinegar (g) = 3.06 Analysis of Vinegar Sample: • Buret reading, initial (mL) = 25.40 • Buret reading, final (mL) = 3.70 . Molar concentration of NaOH solution (mol/L) = 0.0940 Calculate the volume of NaOH used (mL). Number answer only, do not write units. Do NOT write answer in scientific notation.A commercial vinegar is analyzed for the percent acetic acid present. The data for the first trial is given below. Calculate the required quantities using the raw data below. Preparation of Vinegar Sample: • Mass of vinegar (g) = 3.06 Analysis of Vinegar Sample: • Buret reading, initial (mL) = 25.40 • Buret reading, final (mL) = 3.70 • Molar concentration of NaOH solution (mol/L) = 0.0940The following equation describes the oxidation and ethanol to acetic acid by potassium permanganate 3C2H5OH+4KMnO4 —-> 3HC2H3O2 +4MnO2+4 KOH +H2O 5.00 g of ethanol and a excess of aqueous KMnO4 are reacted, and 5.24 g of HC2H3O2 result. What is the percentage yield? A. 100% B. 80.4% C. 26.8% D. 19.6%