Particles A and B are traveling counter-clockwise around a circular track at constant speed vg. If at the instant shown the speed of A is increased by dv/dt = bs4 determine the distance measured counterclockwise along the track from B to A when t = t}. What is the magnitude of the acceleration of each particle at this instant? Given: m vo = 8 - 2 b = 4 5 tį = 1 s r = 5 m e = 120 deg

Your answer is partially correct. The velocity of a particle moving in the x-y plane is given by (7.70i + 4.91j) m/s at time t = 7.38 s. Its average acceleration during the next 0.029 s is (3.3i + 2.6j) m/s?. Determine the velocity v of the particle at t = 7.409 s and the angle 8 between the average- acceleration vector and the velocity vector at t = 7.409 s. Answers: v = ( 7.7957 i+ 4.9754 j) m/s 5.73

A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 2.4t2 - 6.9t and y = 3.2t2 - t/2.2. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 2.9 s. Answers: When t = 2.9 s, V = i mm/s, e, = a = i mm/s?, O = i

Determine the direction of the acceleration of the motorcycle when it reaches B measured counterclockwise from the negative x axis.