At time t = 12 s, the velocity of a particle moving in the x-y plane is v=0.08i +2.28j m/s. By time t- 12.12 s, its velocity has become -0.08i + 2.14j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 8 made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav D i i m/s²

The car A has a forward speed of 21 km/h and is accelerating at 3.0 m/s². Determine the velocity and acceleration of the car relative to observer B, who rides in a nonrotating chair on the Ferris wheel. The angular rate 02-3.2 rev/min of the Ferris wheel is constant. 02=3.2 rev/min B R 8.4 ml j) m/s j) m/s² Answers: VA/B aA/B i i i+ i i+ i

Your answer is partially correct. The velocity of a particle moving in the x-y plane is given by (7.70i + 4.91j) m/s at time t = 7.38 s. Its average acceleration during the next 0.029 s is (3.3i + 2.6j) m/s?. Determine the velocity v of the particle at t = 7.409 s and the angle 8 between the average- acceleration vector and the velocity vector at t = 7.409 s. Answers: v = ( 7.7957 i+ 4.9754 j) m/s 5.73

A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 2.4t2 - 6.9t and y = 3.2t2 - t/2.2. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 2.9 s. Answers: When t = 2.9 s, V = i mm/s, e, = a = i mm/s?, O = i