Part D: Conclusions 28. Do the experimentally determined capacitance measurements match the value marked? Are they close? 29. Would the capacitor discharge more quickly or more slowly if we had used a capacitor with a smaller value of capacitance? Explain. 30. Why does the capacitor charge almost instantly when the switch is closed? 31. Why does the capacitor discharge more slowly when the switch is opened compared to charging?

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Please help solve parts b) and c) only. The correct answer for each part : Part a): 286 Ohm Part b): 6.39 mA Part c): for this one use capacitor operation d = 1.45 mm so solution is 668 V/m Thank you!

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1. Construct a truth table for the figure.2. Obtain the MINTERM expression from the truth table.3. Draw the circuit diagram for the MINTERM expression

Instruction: Answer completely with given, formula, solution, and final answer.

Name The voltage on the capacitor when it is connected to a resistor R follows an exponential rule: Section # capacitor is gradually released as current in the circuit. The energy stored in the capacitor is dissipated in the Pre-lab EM-7 Voltage on a capacitor in an RC Circuit capacitonarged capacitor (at potential Vo) is connected in series with a resistor, the charge stored in the resistor as heat. = Vge (1) where t is the time constant, 1= RC. Vo is the initial voltage on the capacitor when 7= 0. cironpacitance is 220 µF, and the time constant t is 22 seconds, what is the value of the resistance in the circuit? R = In the capacitor is charged to a voltage Vo = 20 V. use this initial value and time constant 22 s to calculate the votage on the capacitor in the circuit at every 5 seconds, List the results in the following table. time t (s) Voltage V (V) V/Vo In (V/Vo) 10 15 20 25 30 35 40 45 50 After the voltage values are calculated, calculate the ratio of V/Vo and In ( V/Vo). EM-7P.1…

In the circuit below, R1 = 300, R2 = 150, R3 = 525, R1 = 300, V = 13. Find the voltage across R1. Please give %3D your answer in Volts. R. R. R,

Please solve sub-parts  c,d,e

Could you help me to solve the following problem step by step?Thank you very much in advance.6. A) How is capacitance defined? B) To a capacitor with air between its plates with an area of 3 cm2 and a separation between them of 1 mm. If a potential difference of 5 V is applied, calculate a) the electric field generated, b) the surface charge density c) the capacitance d) A dielectric of dielectric constant =3 d) What is the capacitance now?