Part A When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.40-cm-tall object is 57.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image. Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated with a comma. ΑΣΦ ? Part B = cm 11 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. Enter your answers in centimeters separated with a comma. ΑΣΦ 82 || = ? cm

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Part A
When two lenses are used in combination, the first one forms an image
that then serves as the object for the second lens. The magnification of the
combination is the ratio of the height of the final image to the height of the
object. A 1.40-cm-tall object is 57.0 cm to the left of a converging lens of
focal length 40.0 cm. A second converging lens, this one having a focal
length of 60.0 cm, is located 300 cm to the right of the first lens along the
same optic axis.
For related problem-solving tips and strategies, you may want to view a
Video Tutor Solution of An image of an image.
Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm.
Enter your answers in centimeters separated with a comma.
ΑΣΦ
?
Part B
=
cm
11 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.
Enter your answers in centimeters separated with a comma.
ΑΣΦ
82 || =
?
cm
Transcribed Image Text:Part A When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.40-cm-tall object is 57.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image. Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated with a comma. ΑΣΦ ? Part B = cm 11 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. Enter your answers in centimeters separated with a comma. ΑΣΦ 82 || = ? cm
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