Part A Use bond enthalpies in the table below to estimate AH for each of the following reactions, Average bond enthalpy (kJ/mol) Br Br C-H: 413 N-H: 391 0-H: 463 F F: 155 C-C: 348 N-N: 163 0-0: 146 Br-C-H + Cl- Cl → Br-C-CI + Cl-H Br Br C=C: 614 N-O: 201 0=O: 495 Cl-F: 253 C-N: 293 N-F: 272 0-F: 190 Cl-Cl: 242 Express your answer in kilojoules to three significant figures. C-0: 358 N-Cl: 200 0-Cl: 203 Br-F: 237 C=0: 799 N-Br: 243 0-I: 234 Br-Cl: 218 C-F: 485 H H: 436 Br-Br: 193 C-Cl: 328 H-F: 567 ΔΗ- kJ C-Br: 276 H-Cl: 431 I-Cl: 208 C-I: 240 H-Br: 366 I-Br: 175 Submit Request Answer H-I: 299 I-I: 151

Nitesh

The lattice energy is defined as the energy required to break one mole of an ionic solid into its ions in the gas phase. The lattice energy for calcium oxide corresponds to the following reaction. CaO(s) Ca2+(g) + O2-(g) DH = ? Using the following information, determine the lattice energy for calcium oxide. Ca(s) ----> Ca(g) DH = 178.2 kJ Ca(g) ----> Ca2+(g) + 2e-   DH = 1747.9 kJ O2(g) ----> 2O(g) DH = 498.3 kJ O2-(g) ----> O(g) + 2e- DH = -702 kJ Ca(s) + 1⁄2 O2(g) ----> CaO(s)   DH = -635.0 kJ   Using the unrounded answer from the previous problem determine q (kJ) for the following reaction when 1.00 grams of solid calcium oxide forms.     Ca2+(g) + O2-(g) ⟶⟶ CaO(s)

! 1 Q :0 F1 Calculate the enthalpy of the reaction below (AHrxn, in kJ) using the bond energies provided. 2 H₂(g) + O₂(g) → 2 H₂O(g). 482 133,809 (a 2 W F2 # 3 E Single Bond M Multiple Bonds I U ZO 80 F3 602 C=O 799 835 C=O 1072 C=N 615 O=O 494 C=N 887 N=N 942 **All values in kJ/mol** oc: 7 11 $ 4 H 432 411 346 386 305 167 459 C=C C=C O CNO a F4 358 201 142 SD F % 5 tv 0 F5 6 Q G F6 NA & 7 F7 G H 33611 RTY U * 8 W F8 ( 9 F9

Use the bond energies provided to estimate AH°rxn for the reaction below. XeF6 AH°rxn = ? Bond Xe-F F-F XeF2+2F2 Bond Energy (kl/mol) 147 159 O-270 kJ +159 kJ -660 kJ +176 kJ -429 kJ K

1. What is the enthalpy of reaction per mole of HCl (g) in the following reaction.( Don't have to explain why) 4HCl (g) + O2 (g) → 2Cl2 (g) + 2H2O + 114.4 kJ a) -457.6 kJ / mol b) -114.4 kJ / mol c) -28.6 kJ / mol d) +114.4 kJ / mol 2. The standard enthalpy of formation of a compound represents: a) The thermal energy released by the decomposition of one mole of this compound. b) The change in enthalpy when a mole of this compound is formed from its elements under standard conditions. c) The change in enthalpy when one mole of an element turns into a compound. d)The thermal energy released by the complete combustion of one mole of this compound. e) The enthalpy change of the phase transition of one mole of this compound.

Calculate the enthalpy of reaction for the combustion reaction (in kJ/mol) shown below. Enter your answer without units. ннно: •. Н-С-С—С—С-Ӧ—Н + 50=0 4 0=c=o° + 4 Н—0—Н ннн Average Bond Energy Bond (kJ/mol) H-H 436 H-C 414 H-O 464 C-C 347 C=C 611 C-0 360 C=O 799 0-0 142 O=0 498 If you cannot see the images above,then click here

Use the data below to calculate the bond energy for a C-F bond in kJ/mol. Bond Energy (kJ/mol) С-Н 413 H-F 567 С-С 347 H-CI .431 F-F 159 H-Br 364 Cl-CI 243 H-I 297. Br-Br 193 I-I 151 The reaction shown below has AH = -3372 kJ as written C2H6lg) + 7 F2(g) → 2 CF4(g) + 6 HFig) In C2H6 each C makes 3 bonds with H and 1 bond with C 485 kJ/mol O 489 kJ/mol O -503 kJ/mol O none of the answers are correct

Use the bond energies provided for the question

Determine the enthalpy change for  combustion of using bond energies for             2C2H6(g)  + 7O2(g)  ➜ 4CO2(g)  + 6H2O(l) see image