An object is placed 16.0 cm to the left of a converging lens that has a focal length  f1 = +12.4 cm.  How far is the image from the lens? (Give your answer to at least one decimal place.) A screen is placed 71.1 cm to the right of the converging lens. A diverging lens is placed between the converging lens and the screen. When the diverging lens is 42.7 cm to the right of the converging lens the image formed by the lens combination is located at the screen. What is the focal length f2 of the diverging lens?

A glass (n=1.5) biconvex lens has radii of curvature of +15 cm and -18 cm. If an object is placed at 10 cm left of the left surface of the lens, what is the image distance? Calculate the magnification and orientation of the image.

please answer parts b, c, and d

A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College Physic