Part A How much heat is exhausted to the cold reservoir by the heat engine shown in (Figure 1)? Express your answer with the appropriate units. HA Qc = Value J Submit Request Answer Figure < 1 of 1 > Provide Feedback p (kPa) 225 J 300 - 200- 90 J 100 - V (cm³) 600 300
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- The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093An electric heater producing 260 W of heat is used to warm up a room containing 7 m3 of air. If we assume the room is perfectly sealed and there is no heat loss through the room boundaries, such that all of the heater output goes into increasing the air temperature, how long will it take to heat up the air in the room from 5.0 °C to 24.1 °C? Give your answer to the nearest minute and assume that the specific volume (v = 0.85 m3/kg) and specific heat capacity at constant volume (cv = 1.005 kJ/(kg K)) remain constant throughout the heating process.An air conditioner supplies cold air at the same temperature to each room on the fourth floor of the building shownin Fig. The floor plan is shown in Fig. The cold air flow produces an equal amount of heat flow ݍ out of each room. Write a set ofdifferential equations governing the temperature in each room, where To= temperature outside the building, Ro= resistance to heatflow through the outer walls, Ri= resistance to heat flow through the inner walls. Thermal capacitance of each room is C. Assumethat (1) all rooms are perfect squares, (2) there is no heat flow through the floors or ceilings, and (3) the temperature in each roomis uniform throughout the room. Take advantage of symmetry to reduce the number of differential equations to three.
- Q3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues using MATLAB: dTglass = -0.75Tgtass + 0.75TpvT (1) dt - 1.187glass – 22Tpyr + 23Twax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tgtass , TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold suppty In frem water Tank Glass PVT Espann Nane-PCMPVT Collector Wax Tubes Sterg Tank Nanofluid Heat Exchanger Contalner Tepe Teek oe Pump for drainQ3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues dTglass = -0.75Tglass + 0.75TPVT (1) dt - 1.18Tglass – 22TpyT + 237wax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tptass, TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold sappty In frem water Tank Glass PVT Enpann Nane-PCMPVT Collector Wax Tubes Sterg Tank Mat Nanofluid Heat Exchanger Tepe Contalner Tuek et Pump for drain10. From Newton's law of cooling, the boiled egg submersed in water in the diagram below will cool according to dI = -0. 1(T – a), T(0) = 100°C . Solve this differential equation and express T in terms of a. Do not use the integrating factor method. Present your solution with T as the subject. Use your solution to solve the following: If after 1 = 10 time units this egg cools to T = 2ª°C , what was the value of a (a is the temperature of the water in the glass which is assumed to have remained constant)?
- The rate of heat flow equation is Q O A. Thermal resistance OB. Thermal coefficient O C. None of these OD. Thermal conductivity Type here to search KA(T₁-T₂) X E The term X ΚΑ is known as 99+Jes 1:01 i docs.google.com/forms what is the Physicists recognize four fundamental forces.* Flectrical force O - Gravitational force -Strong nuclear force Weak nuclear force O -Muscular force Force of friction Ff is described by • Ff = µN * O p synovlal fluld in the Joints P -coefficient of fraction between two surface in The temperature of the human body is normally about 98.6°F.calculate the temperature of the body "C* oC = (5/9)x(oF-32) =5/9(98.6- 32)-37 oc oc=(9/5)x(of -32) =9/5(98,6-32) =13,3 Under resting conditions the body energy is being used as follows * O 27% by the liver and splee O 20-%by the skeletal musules Under resting conditions the body energy is being used as follows. O 19% by the brain. 15% by the kidney. We can write the first law of thermodynamics as: * O AU-AQ -A.. O AU-AQ +AW. 1kcal = J O 1 Kcal =4184j. O O O OStep by step solution and answer thank youuu
- Solve correctly please. Water with a bulk temperature of 70 F flows through a 2-inch chart 80 steel pipe. The temperature of the steam condensing outside the pipe is 210 F and the heat transfer rate is 1600 Btu/h F Rr. If the heat transfer coefficient of the current flowing through the pipe is 400 Btu/hr F, calculate the heat transfer rate in kW for 1 m of pipe. (Gpt/ ai wrong answer not allowed)Qi: (50 marks) Find the total heat flux of the composite wall when: B KA = KC = KF = 15 m. K KB = KD = 10 m. K KE = KG = 20 %3D m. K D. Height of B = C = D 4 cm 3 cm 4 cm 6 cm Height of F = G AT = 30 KNewtons laws of cooling proposes that the rate of change of temperature is proportional to the temperature difference to the ambient (room) temperature. And can be modelled using the equation: dT/dt = -k (T-Ta)It can also be written as dT/T-Ta = -k dtWhere:T = Temperature of materialTa = Ambient (room) temperaturek = A cooling constanta) integrate both sides of the equation and show that the temperature difference is given by:(T-Ta) = CoE^-kt(Co is a constant for this problem)B) calculate Co if the initial temperature is 70 degrees C and Ta = 20 degrees C?