▾ Part A For the reaction Ke=82.8 at a temperature of 169 °C. Calculate the value of K Express your answer numerically. ▸ View Available Hint(s) K₂ 5.07 107 Submit Previous Answers VO AXp Part B X Incorrect; Try Again; 5 attempts remaining For the reaction Kp1.06x10-2 at a temperature of 151 °C. Calculate the value of K. Express your answer numerically. ▸ View Available Hint(s) K₂= Submit ? ΠΟΙΑΣΦ ? 3A(g) + 3B(g) = C(g) X(g) + 2Y(g) 3Z(g)

Mercury(IT) oxide decomposes to form mercury and oxygen, like this: 2HgO(s)--2Hg(l)+O2(g) At a certain temperature, a chemist finds that a 3.5 L reaction vessel containing a mixture of mercury (It) oxide, mercury, and oxygen at equilibrium has the following composition: compound amount HgO 15.3 g Hg 19.1 g O2 25.0 g Calculate the value of the equilibrium constant K, for this reaction, Round your answer to 2 significant digits.

Aa.49.

7.B Consider the chemical equation C(s) + 2A(g) 5 2B(I) + heat. Be sure to briefly JUSTIFY each answer below. (a) Will SQUEEZING the container cause a disturbance to equilibrium? If so, then in what direction will the reaction occur? (b) Will RAISING THE TEMPERATURE of the system cause a disturbance to equilibrium? If so, then in what direction will the reaction occur? (c) What is the sign of the standard reaction ENTHALPY? Does the enthalpy change provide a favorable or unfavorable contribution to the spontaneity of the forward reaction at standard state conditions? (d) What is the sign of the standard reaction ENTROPY? Does the entropy change provide a favorable or unfavorable contribution to the spontaneity of the forward reaction at standard state conditions? (e) Based on (c,d) describe the preference for products or reactants at equilibrium at very LOW temperatures. (f) Based on (c,d) describe the preference for products or reactants at equilibrium at very HIGH temperatures.