Part 7 of 8 - Analyze Now the friends try a homework problem. A capacitor is constructed with two parallel metal plates each with an area of 0.56 m² and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the electric field in the region between the two plates. 625 ✓ V/m Find the charge Q. 1.97e-10 X C Find the capacitance of the parallel plates. x 10-6 F Submit Submit Answer Skip (you cannot come back)

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter27: Capacitors And Batteries
Section: Chapter Questions
Problem 40PQ
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O"Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C =
EA
d
O "Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C =
d
E0A
O "Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C = 47€ A."
AV
d
O "Solve E =
Part 7 of 8 - Analyze
Now the friends try a homework problem.
for AV, and substitute into Q = CAV."
A capacitor is constructed with two parallel metal plates each with an area of 0.56 m² and separated by d = 0.80 cm. The
two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each
of the oppositely charged plates.
Find the electric field in the region between the two plates.
625
✔V/m
Find the charge Q.
1.97e-10 X C
Find the capacitance of the parallel plates.
x 10-6 F
Submit Skip
Submit Answer
Skip (you cannot come back)
(you cann
"
Transcribed Image Text:O"Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C = EA d O "Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C = d E0A O "Use Q = CAV, with the expression for the capacitance of a parallel-plate capacitor, C = 47€ A." AV d O "Solve E = Part 7 of 8 - Analyze Now the friends try a homework problem. for AV, and substitute into Q = CAV." A capacitor is constructed with two parallel metal plates each with an area of 0.56 m² and separated by d = 0.80 cm. The two plates are connected to a 5.0-volt battery. The current continues until a charge of magnitude Q accumulates on each of the oppositely charged plates. Find the electric field in the region between the two plates. 625 ✔V/m Find the charge Q. 1.97e-10 X C Find the capacitance of the parallel plates. x 10-6 F Submit Skip Submit Answer Skip (you cannot come back) (you cann "
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