Sand cone equipment is used to performField density test on a compactedarth fil.Soil sample dug from the test hole= 19.88 NDry weight of soil sample = 17.92 NOttawa sand used to fill the hole weighs16.05 N and is known to have a densityof 15.74 HN/m.Which of the following gives the watercontent of the tested soil?O a. 15.45%O b. 12.08%O c. 14.96%O d. 10.94%e.11.12%

Weight of soil=19.88N Weight of dry soil=17.92N

Answered: pand cone equipment is Used to perform…

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Improvement And Ground Modification

Section: Chapter Questions

Problem 5.2P

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3. A dry sand is placed in a container 9 cm3. The dry weight of the sample is 15 g. Water is carefully added to the container so as not to disturbed the condition of the Sample. When the container is filled the combined weight of soil and water is 18 g. Determine the following: a) Void ratio of sample in the container b) Porosity c) Water constant d) Specific gravity of the soil particle e) Saturated unit weight f) Dry unit weight
1. Sand cone equipment is used to determine an in-place unit weight (field density test) on a compacted earth fill. Ottowa sand is used in the cone and is known to have a bulk density of 100 pcf. a. From the information given below, determine the in-place dry unit weight of the tested soil, and the water content. Soil sample dug from test hole wet weight = 4.62 lb Dried Weight of soil sample = 4.02 lb Weight of Ottowa Sand (Sand Cone) to fill test hole = 3.60 lb b. Determine the percentage of compaction of the tested soil if the laboratory moisture unit weight curve indicates a dry unit weight of 115 pcf and optimum moisture content of 13 percent.
A dry sand is placed in a container having a volume of 0.0089 cm³. The dry weight of the sample is [0.010+(0.001*A)] grams. Water is carefully added to the container so as not to disturb the condition of the sand. When the container is filled, the combined weight of soil plus water is [0.0100+(0.001*B)+(0.0001*C)] grams. Determine: (Note: if your answer in any of the following is negative, continue solving anyway,) a) Moisture content b) Moist unit weight c) Dry unit weight Let A = 1 B = 6 C = 3
An in-place density determination (in-place unit weight) is made for the sand in a borrow pit using a balloon-type density apparatus. The damp sample dug from a test hole is found to weigh 37.90 N. The volume of the test hole is 0.00184m2. A. Compute the wet unit weight. B. This soil is to have a water content of 15%. Compute the dry unit weight of the soil. C. Compute the specific gravity of the soil if it has a void ratio of 0.423
Sand cone equipment is used to perform a field density test on a compacted earth fill. • Soil sample dug from the test hole = 20.60 N • Dry weight of soil sample = 17.92 N Ottawa sand used to fill the hole weighs 16.05 N and is known to have a density of 15.74 kN/m3. Determine the in-place dry density of the tested soil. Answer:
Sand cone equipment is used to perform a field density test on a compacted earth fill. • Sil sample dug from the test hole = 20.60 N • Dry weight of soil sample = 17.92 N Ottawa sand used to fill the hole weighs 16.05 N and is known to have a density of 15.74 kN/m³. Which of the following gives the water content of the tested soil? O a. 15.45% O b. 12.08% O . 11.12% d. 14.96% e. 10.94% Clear my choice
(b) Classification tests for the determination of the particle size distribution of a soil produced the following results: Particle Size % finer (mm) 99 2.36 80 1.3 63 0.6 33 0.2 10 0.075 3 0.02 Then using cone penetrometer for Liquid Limit test, the results were recorded as follows. Cone penetration 15.9 17.7 19.1 20.3 22.5 (mm) Water 32.6 42.9 51.6 59.8 66.2 content (%) While the plastic limit test conducted for the same soil recorded as below:- Test No. 1 2 3 Wet soil 10.01 11.23 9.72 Dry soil 8.02 9.01 7.72 SKAA 1713 4 i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b). Calculate the uniformity coefficient, Cu and the coefficient of gradation, C, for the soil sample. Determine the plastic limit, the liquid limit and the plasticity index of the soil. Plot the graph to help you obtain the results (if necessary). ii) iii)
Refer to the soil in Problem 4.5. Using the Casagrande plasticity chart, graphically estimate the shrinkage limit of the soil as shown in Figure 4.22. 4.5 The following data were obtained by conducting liquid limit and plastic limit tests on a soil collected from the site. Liquid limit tests: Plastic limit test: PL = 19.3% a. Draw the flow curve and determine the liquid limit. b. Using the Casagrande plasticity chart (Figure 4.21), determine the soil type.
1. A dry sand is placed in a container having a volume of 0.0092 cubic centimeter. The dry unit weightof the sample is 0.015 gram. Water is carefully added to the container so as not to disturbed thecondition of the sand. When the container is filled, the combined weight of soil plus water is 0.0182gram.a. Determine the specific gravity of soil particle.b. Determine the dry unit weight of soil.2. If the soil sample has a water content of 11% and a unit weight of 19.67 kN/m3 , determine thepercentage of air in voids and the degree of saturation if the specific gravity of soil solid is 2.75.3. If the soil sample has a specific gravity of 2.71 and a porosity of 0.345, determine the saturated unitweight and the bouyant unit weight.4. A soil sample having a liquidity index of 0.85, a plasticity index of 16.50 and a plastic limit of 11.45.The soil sample has a specicfic gravity of 2.68 and a void ratio of 0.77.a. Compute the degree of saturation.b. Compute the air void ratio.
a .l zain IQ elearning7.uokufa.edu.iq CHAPTER SEVEN STERSSES WITHIN SOIL MASS Н.W The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty clay with sand are shown in the table below. Determine the maximum dry unit weight and optimum water content. Diameter of mould = 4 in. Height of mould 4.584 in. Volume of mould = 1/30 ft3. Weight of mould, M = 4.45 lb. Unit weight data Water content data Weight of wet soil and mold (Ibs) Mass of can and wet soil (grams) Mass of can and dry soil (grams) Mass of can (grams) M. M. M. 7.32 114.92 111.48 7,57 163.12 155.08 7.68 190.43 178.64 46.20 193.13 178.24 46.50 7.65 188.77 171.58 46.10 II
A dry sand is placed in a container having a volume of 0.30cu.ft. The dry weight of sample is 31lb. Water is carefully added to the container so as not to disturb the condition of the sand. When the container is filled, the combined weight of soil llus water is 38.2 lb. a. Compute the void ratio in the container. b. Compute the specific gravity of the soil particle. c. Determine the dry unit weight.
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.

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