Find P(A or B or C) for the given probabilities. P(A) = 0.33, P(B) = 0.24, P(C)= 0.19 P(A and B) = 0.11, P(A and C) = 0.02, P(B and C) = 0.09 P(A and B and C) = 0.01 P(A or B or C) =

U and V are mutually exclusive events. P(U) = 0.21; P(V) = 0.6. Find: a. P(U and V) = b. P(UIV) = c. P(U or V) =

Given two events G and H, the probabilities of each occurring are as follows: P(G) = 0.5; P(H) = 0.31; P(H AND G) =0.09.  Using this information:  Find the complement of P(H OR G).

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Given that P(A)P(A) = 0.62, P(B)P(B) = 0.27, and P(A∣B)P(A∣B) = 0.22, find the probabilities:P(B∣A)P(B∣A) = P(∼A)P(∼A) = P(∼B)P(∼B) = P(∼A∣B)P(∼A∣B) = P(∼B∣A)P(∼B∣A) = P(A∣∼B)P(A∣∼B) = P(B∣∼A)P(B∣∼A) =

hwm7 7 Use the following probabilities to answer the question. P(A) =0.6, P(B)=0.35 AND P(AandB)=0.05. P(notB notA)=  _%

Sociologists say that 95% of married women claim that their husband's mother is the biggest bone of contention in their marriages (sex and money are lower-rated areas of contention). Suppose that seven married women are having coffee together one morning. Find the following probabilities. (For each answer, enter a number. Round your answers to three decimal places.)   At least five of them dislike their mother-in-law. (d) No more than four of them dislike their mother-in-law.

Suppose we know that the probabilities P(A) = .5, P(B|A) = .3 and P(A or B) =.3. What is the value for P(A and B)? What is the value for P(B)?

K Find P(A or B or C) for the given probabilities. P(A)=0.39, P(B) = 0.22, P(C) = 0.11 P(A and B) = 0.12, P(A and C) = 0.02, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =