Find P(A or B or C) for the given probabilities.P(A) = 0.33, P(B) = 0.24, P(C)= 0.19P(A and B) = 0.11, P(A and C) = 0.02, P(B and C) = 0.09P(A and B and C) = 0.01P(A or B or C) =

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Answered: Find P(A or B or C) for the given…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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K Find P(A or B or C) for the given probabilities. P(A)=0.39, P(B) = 0.22, P(C) = 0.11 P(A and B) = 0.12, P(A and C) = 0.02, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =
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Use the following probabilities to answer the question. Round to 4 decimal places.P(A)=0.54P(A)=0.54 , P(B)=0.41P(B)=0.41 , P(AandB)=0.05P(AandB)=0.05 .P(B∣A)=
Listed are two events A and B. Below are the probabilities. P(A)= 0.5 P(B)= 0.4 P(A u B)=0.65 Please find out whether A and B are independent .
The probability of an integrated circuit passing a quality test is F. In a batch of 10 integrated circuits find the probabilities thati. 2 will failii. 8 will passiii. at least 2 will failiv. fewer than 2 will fail.
You are enrolled in MBA 440. At the beginning of the semester, you used your hunch to estimate the likelihood of passing this class. Let P be the event of passing the class; F is the event of failing the class. Your prior probabilities are as follows: P(P)=0.7 P(F)=0.3 After the first week of class, you find out that you have failed the first assignment. Let A1 be the event of passing the first assignment; let A2 be the event of failing the first assignment. Now you feel you need to update your belief about the likelihood of passing this class. You talk to your Professor and she tells you that given someone has passed the class, the probability of passing the first assignment is 0.8, i.e. P(A1|P)=0.8. She also gives you the following conditional probabilities: P(A2|P)=0.2; P(A1|F)=0.3 and P(A2|F)=0.7. What is the posterior probability that you will pass this class given that you have failed the first assignment?
Brian, a landscape architect, submitted a bid on each of three home landscaping projects. He estimates that the probabilities of winning the bid on Project A, Project B, and Project C are 0.7, 0.5, and 0.2, respectively. Assume that the probability of winning a bid on one of the three projects is independent of winning or losing the bids on the other two projects. Find the probability that Brian will experience the following. (a) Win all three of the bids (b) Win exactly two of the bids (c) Win exactly one bid
Find P(A or B or C) for the given probabilities. P(A) = 0.34, P(B) = 0.25, P(C) = 0.16 P(A and B) = 0.11, P(A and C) = 0.03, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =
Use the following probabilities to answer the question. Round to 4 decimal places.P(A)=0.26P(A)=0.26, P(B)=0.69P(B)=0.69, P(AandB)=0.05P(AandB)=0.05.P(B∣A)=
At the beginning of each day, a patient in the hospital is classifed into one of the three conditions: good, fair or critical. At the beginning of the next day, the patient will either still be in the hospital and be in good, fair or critical condition or will be discharged in one of three conditions: improved, unimproved, or dead. The transistion probabilities for this situation are Good Fair Critical Good 0.65 0.20 0.05 Fair 0.50 0.30 0.12 Critical 0.51 0.25 0.20 Improved Unimproved Dead Good 0.06 0.03 0.01 Fair 0.03 0.02 0.03 Critical 0.01 0.01 0.02 For example a patient who begins the day in fair condition has a 12% chance of being in critical condition the next day and a 3%…
John is having a dinner at a restaurant, which sells 3 kinds of dishes, A, B, and C. The probabilities of ordering each dish are 0.4, 0.3, and 0.3. Suppose the probability of John being satisfied after eating the dishes are 0.7, 0.5, and 0.6, respectively. Answer the questions below. 1) When John wasn’t satisfied with his dish, what is the probability that he has eaten the dish B? (Round an answer to two decimal places.) 2) What is the probability that John satisfies after eating the dish?

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Find P(A or B or C) for the given probabilities. P(A) = 0.33, P(B) = 0.24, P(C)= 0.19 P(A and B) = 0.11, P(A and C) = 0.02, P(B and C) = 0.09 P(A and B and C) = 0.01 P(A or B or C) =