Out of 600 people sampled, 402 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

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Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

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Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

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Q: Out of 400 people sampled, 344 had kids. Based on this, construct a 99% confidence interval for the…

A: Given that sample size n = 400 Number of peoples with kids, X = 344 The critical value of Z at 99%…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500…

A: The sample proportion of the sample of size n can be defined as:  Here, X = Total number of success…

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

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Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

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Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

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Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

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Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: Out of 100 people sampled, 44 have lied to a family member in the past month. Based on this,…

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Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: From a lake, an unknown proportion of fish have been tagged.  You collect a sample of 100 fish taken…

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Q: A survey showed 980 of 1500 adult respondents believe in global warming. Construct a 95% confidence…

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Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

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Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

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Q: Out of 400 people sampled, 76 had kids. Based on this, construct a 90% confidence interval for the…

A: Find z-critical value:…

Q: Out of 42738 freshmen entering the State University system,  27298 of them need to take remedial…

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Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: Out of 400 people sampled, 336 had kids. Based on this, construct a 95% confidence interval for the…

A: Given that out of 400 people sampled, 336 had kids.  95% confidence level

Q: Out of 400 people sampled, 276 had kids. Based on this, construct a 90% confidence interval for the…

A: For 90% confidence intervalα=1-CI=1-0.90=0.10So, zα2=z0.102=z0.05=1.645