our simple 2-stage pipeline, we run a particular benchmark pro- gram and fnd that it has 19% conditional branches. An additional 4% are unconditional branches. What is the maximum number of the conditional branches that could be taken if we want to keep the CPI to 1.10 or less? what is the minimum percentage of branch delay slots that need to be filled with useful instructions in order to keep the CPI to 1.0135?

Vidyadhar, Rodika, and Manoj write code for a system that requires 4 modules.  Each module takes an exponential amount of time to complete with mean 3.0 days.  Once a coder is finished with a module, he/she starts another, but only one coder can work on a module.  Let {X(t), t >=0} be the CTMC describing the number of modules remaining to code. Show the rate diagram for X Show the Q matrix

Suppose we have four machines that are using the Berkeley algorithm for clock synchronization. The time daemon is running on machine MO. The other machines are named M1, M2, and M3. The time readings on the four machines are as follows wenty-four hour clocks are usedt. MO 09:10 M1: 08:30 M2 10:10 M3: 07:14 In the third step of the algorithm, what are the values that the time daemon sends to each machine? Assume that the time values are expressed in minutes. Below, these values are presented in a vector value sent to MO, value sent to MI, value sent to M2. value sent to M3I none of these O84, 44, 96, 321 O(24, 16, -84, 92) O192. 84, 16. -24 O-32, 76, 40

#ammend this code for the inputs (x = 5.01, 4.99, 0, -2.01, -1.99) so that there is a tolerance/Leeway for the values off > #such that 4.99 prints blue and -2.01 prints orange. # cannot adjust the value to x > 4.99 instead of 5 must add new code to add a tolerance or Leeway if x > 5: print ("blue") elif x < -2: print ("orange") else: print("purple")

E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable code

I need help with my MATLAB code. I wanted to numerically integrate MRPs. When there was a singularity in MRP, my code would stop it using an event function. Now, I want to switch to the MRP shadow set and run the ode45 again with the updated initial conditions. How do I do that?   clc;clear all; w0 = [0; 0; 0.3]; MRP0 = [0; 0; -0.198912367379658];tspan = [0, 100]; % Integrate the Euler equations using ode45 with an event functionoptions = odeset('RelTol', 1e-10, 'AbsTol', 1e-10, 'Events', @singularityEvent);[t, y, te, ye, ie] = ode45(@KDE_MRP, tspan, [MRP0; w0], options); % Extract the Euler parameters and angular velocitiesMRP = y(:, 1:3);w = y(:, 4:6); % plotting MRP vs timeplot(t,MRP, '-')xlabel('time (s)')ylabel('MRP')legend('MRP1', 'MRP2', 'MRP3') function [value, isterminal, direction] = singularityEvent(t, MRPw)    % Event function to detect when the norm of MRP approaches 2    value = norm(MRPw(1:3)) - 1;    isterminal = 1;  % Stop the integration when the event is detected…