Order the following bonds from most polar to least polar: M-E L-G D-Q Group of answer choicesM-E > L-G > D-QD-Q < L-G > M-EM-E > D-Q > L-GL-G > D-Q > M-E **Ordering Bond Polarity Based on Electronegativity****Question:**Order the following bonds from most polar to least polar: M-E, L-G, D-Q.---**Table of Fictitious Electronegativity Values:**- A: 2.5- D: 2.3- E: 3.2- G: 3.6- J: 4.0- L: 1.8- M: 2.6- Q: 3.0- R: 3.3---**Options:**1. M-E > L-G > D-Q2. D-Q < L-G > M-E3. M-E > D-Q > L-G4. L-G > D-Q > M-E**Explanation of Electronegativity:**Electronegativity is the tendency of an atom to attract electrons in a chemical bond. The difference in electronegativity between two atoms in a bond determines the bond's polarity. A larger difference results in a more polar bond.To determine bond polarity:- **M-E (2.6 and 3.2):** Difference of 0.6- **L-G (1.8 and 3.6):** Difference of 1.8- **D-Q (2.3 and 3.0):** Difference of 0.7Calculate the difference for each bond to order them from most polar to least polar.**Correct Order:** L-G > D-Q > M-EThis order is selected based on the calculated differences in electronegativity, identifying the bond with the greatest difference as the most polar.

Polarity of a bond can be determined from the difference in electronegativity of the atoms. Given that , Electronegativity value of M = 2.6 Electronegativity value of E= 3.2 Electronegativity value of D = 2.3 Electronegativity value of Q = 3.0 Electronegativity value of L = 1.8 Electronegativity value of G = 3.6When electronegativity between the atoms increases, polarity of the bond increases. If the electronegativity difference is less than or equal to 0.40, the bond is considered to be a non polar bond and if it is above 0.40, the bond is considered to be a polar bond. So now let us check the electronegativity difference of M-E , L-G and D-Q For M-E, electronegativity difference = (Electronegativity value of E - Electronegativity value of M) = (3.2 - 2.6) = 0.6 For L-G, electronegativity difference = (Electronegativity value of G - Electronegativity value of L) = ( 3.6 - 1.8 ) = 1.8 For D-Q, electronegativity difference = (Electronegativity value of Q - Electronegativity value of D) = ( 3.0 - 2.3 ) = 0.7 From the above calculation, it is clear that electronegativity difference is more for the bond L-G and least for the bond M-E. So bond L-G with more electronegativity difference is more polar among the given bonds. Hence the order from most polar bond to the least polar bond is L-G > D-Q > M-E