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or Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. ??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq) Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction {Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x                           ["", "", "", ""]              {HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x

or Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. ??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq) Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction {Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x                           ["", "", "", ""]              {HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For Questions 11-16:

Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question.

??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq)

Step 5: Make the number of electrons in each half reaction equal by finding the multiplying factor for each half reaction

{Cr2O7-2(aq) + 14H+ (aq) +6e- ⟶⟶ 2Cr+3(aq) + 7 H2O (l) } x                           ["", "", "", ""]           

 

{HNO2(aq) + H2O (l) + ⟶⟶ NO3-(aq) + 3H+ (aq) + 2e- } x

 

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