For a 3-cm thick slab that can be taken to be infinite in the x- and y-directions, the steady temperatures at z = 0 and z=3 cm are 97°C and 27°C, respectively. a) Compute the heat flux vector through the slab for k= 2.1 W/(m K). b) Compute the heat flux vector through the slab for k= [2.1 +0.05(T-300 K)/K] W/(m K). c) Compute the heat flux vector through the slab for k= [2.1 +0.05(T-62°C)/K] W/(m K).

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Chapter2: Steady Heat Conduction
Section: Chapter Questions
Problem 2.52P
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For a 3-cm thick slab that can be taken to be infinite in the x- and y-directions, the steady
temperatures at z = 0 and == 3 cm are 97°C and 27°C, respectively.
a) Compute the heat flux vector through the slab for k= 2.1 W/(m K).
b) Compute the heat flux vector through the slab for k= [2.1 +0.05(T-300 K)/K] W/(m K).
c) Compute the heat flux vector through the slab for k = [2.1 +0.05(T-62°C)/K] W/(m K).
Transcribed Image Text:For a 3-cm thick slab that can be taken to be infinite in the x- and y-directions, the steady temperatures at z = 0 and == 3 cm are 97°C and 27°C, respectively. a) Compute the heat flux vector through the slab for k= 2.1 W/(m K). b) Compute the heat flux vector through the slab for k= [2.1 +0.05(T-300 K)/K] W/(m K). c) Compute the heat flux vector through the slab for k = [2.1 +0.05(T-62°C)/K] W/(m K).
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