Only 3 and 4
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Only 3 and 4
![1.Find the exact step counts (growth function) and time complexity for following algorithms -
i.
1.Input m and n
2.If m == n
ii.
iii.
Algorithm Add(a,b,c,m,n)
1. for i:=1tom do
for i :=1to n do
c[ij]:=a[i, j]+b[ij];
1. Initialize i =0
2. For i=0 to n-1
3.
Print "Same"
3.
Read an integer in Arr[i]
2.
4. For i-0 to n-1
Print Arr[i]
4.
Sum=m+n
3.
5.
Print Sum
5.
6.Else Print "Not same"
vi.
iv.
V.
1. sum = 0
1.int i, j, k = 0;
Algorithm Sum (a,n)
2. for i = 1 to n:
1 s:=0.0;
2.for (i =1; i<= n*n; i++)
for (j = 1; j <= n; j= j +1)
k = k + n/2;
3.
for j = i to n:
for i:=1to n do
s:=s+a[i];
3.
4.
4.
sum += a[i][)
4 return s;
5. print(sum)
vii.
viii.
ix.
1. Set i =0
2. Repeat step 3-6 till i<=n
3.
1. Set I =n
2. While I>1
void fun(int n, int arr[])
1. {
int i = 0, j = 0;
for(; i<n; ++i)
while(j<n && arr[i] < arr[j])
j++;
Set J=n
3.
J=1
2.
4.
While J>0
4.
While J<n
3.
5.
J= J/2
5.
K=1
4.
6.
i=i+1
6.
While K <n
5.
7.
K += 2
6. }
8.
J *= 2
9.
I/= 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e1264d1-2615-455e-a0fd-010b44cfb1c9%2Ff6209212-111f-4f6c-924d-291e98b0d5f0%2Fd1eo4y7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.Find the exact step counts (growth function) and time complexity for following algorithms -
i.
1.Input m and n
2.If m == n
ii.
iii.
Algorithm Add(a,b,c,m,n)
1. for i:=1tom do
for i :=1to n do
c[ij]:=a[i, j]+b[ij];
1. Initialize i =0
2. For i=0 to n-1
3.
Print "Same"
3.
Read an integer in Arr[i]
2.
4. For i-0 to n-1
Print Arr[i]
4.
Sum=m+n
3.
5.
Print Sum
5.
6.Else Print "Not same"
vi.
iv.
V.
1. sum = 0
1.int i, j, k = 0;
Algorithm Sum (a,n)
2. for i = 1 to n:
1 s:=0.0;
2.for (i =1; i<= n*n; i++)
for (j = 1; j <= n; j= j +1)
k = k + n/2;
3.
for j = i to n:
for i:=1to n do
s:=s+a[i];
3.
4.
4.
sum += a[i][)
4 return s;
5. print(sum)
vii.
viii.
ix.
1. Set i =0
2. Repeat step 3-6 till i<=n
3.
1. Set I =n
2. While I>1
void fun(int n, int arr[])
1. {
int i = 0, j = 0;
for(; i<n; ++i)
while(j<n && arr[i] < arr[j])
j++;
Set J=n
3.
J=1
2.
4.
While J>0
4.
While J<n
3.
5.
J= J/2
5.
K=1
4.
6.
i=i+1
6.
While K <n
5.
7.
K += 2
6. }
8.
J *= 2
9.
I/= 2
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