**Title:** Investigating Changes in the Mean Age of Death-Row Inmates**Background:**One year, the mean age of an inmate on death row was recorded as 40.5 years. A sociologist was curious to see if this mean age has changed over time. **Study Design:**- The sociologist randomly selected 32 death-row inmates.- The mean age of these selected inmates was calculated to be 39.5 years.- The standard deviation of their ages was found to be 8.2 years.**Objective:**Construct a 95% confidence interval for the mean age of death-row inmates to determine if there is a significant change from the previously recorded mean of 40.5 years.**Instructions:**- Click the icon to view the table of critical t-values for precise calculations.**Hypotheses:**- **$ H_0 $:** $\mu = 40.5$ - **$ H_1 $:** $\mu \neq 40.5$ *(Note: Choose the correct hypothesis by selecting the appropriate symbols and values. Type integers or decimals exactly as needed; do not round.)* This study focuses on understanding whether there is a statistical difference in the mean age of death-row inmates compared to previous data.

Answered: Image /qna-images/answer/14c1285d-4823-4831-8d32-92779851031e.jpg

Answered: One year, the mean age of an inmate on…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The capacities (in ampere-hours) were measured for a sample of 120 batteries. The average was 178 and the standard deviation was 14. a.Find a 99%lower confidence bound for the mean capacity of this type of battery. b. An engineer claims that the mean capacity is greater than 174 ampere-hours. With what level of confidence can this statement be made?
A study that looked at beverage consumption used sample sizes that were much smaller than previous national surveys. One part of this study compared 20 children who were 7 to 10 years old with 5 who were 11 to 13. The younger children consumed an average of 8.5 oz of sweetened drinks per day while the older ones averaged 14.5 oz. The standard deviations were 10.9 oz and 8.5 oz respectively.Use younger children as population 1. (a) Do you think that it is reasonable to assume that these data are Normally distributed? Explain why or why not. (Hint: Think about the 68-95-99.7 rule.) O The distributions appear to be Normal according to the 68-95-99.7 rule. We can see that the groups have means and standard deviations, two characteristics of Normal distributions. O The 68-95-99.7 rule suggests that the distributions are not Normal. If they were, we would expect some of the children to drink negative amounts of sweetened drinks, which does not make sense. (b) Using the methods in this…
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
here’s the question to 6.27 since 6.29 needs it
One year the ACT had a mean score of 22.7 and a standard deviation of 4.1. minutes. (a)Calculate the z-score of an ACT score of 25. Interpret it using a complete sentence. B. What ACT score is 1.5 standard deviations above the mean? What can you say about this consumption
Sam is the manager of a used clothing store. He wants to estimate the average amount a customer spends per visit. A random sample of 70 customers’ receipts gave a mean of = $7.10 with a standard deviation s = $2.30. Find a 99% confidence interval for the average amount spent by all customers. Interpret your findings.
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Use z scores to compare the given values. The tallest living man at one time had a height of 252 cm. The shortest living man at that time had a height of 53.2 cm. Heights of men at that time had a mean of 172.68 cm and a standard deviation of 8.46 cm. Which of these two men had the height that was more extreme? see score past due Since the z score for the tallest man is z=] and the z score for the shortest man is z= the height that was more extreme. (Round to two decimal places.)
A statistics professor announces that 15% of the grades he gives are As. The results of the final examinations indicate that the mean score is 83, with a standard deviation of 6. What minimum score must a student get to receive an A?
One year, the mean age of an inmate on death row was 38.5 years. A sociologist wondered whether the mean age of a death-row inmate has changed since then. She randomly selects 32 death-row inmates and finds that their mean age is 37.9, with a standard deviation of 8.8. Construct a 95% confidence interval about the mean age. What does the interval imply? E Click the icon to view the table of critical t-values. Choose the correct hypotheses. Ho: H,: (Type integers or decimals. Do not round.) Construct a 95% confidence interval about the mean age. With 95% confidence, the mean age of a death row inmate is between years and years. (Round to two decimal places as needed.) What does the interval imply? O A. Since the mean age from the earlier year is contained in the interval, there is not sufficient evidence to conclude that the mean age had changed. O B. Since the mean age from the earlier year is contained in the interval, there is sufficient evidence to conclude that the mean age had…

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