You can retry this question belowThe mean number of English courses taken in a two-year time period by male and female collegestudents is believed to be about the same. An experiment is conducted and data are collected from26 males and 20 females. The males took an average of 3.7 English courses with a standarddeviation of 0.3. The females took an average of 3.6 English courses with a standard deviation of 0.6.Conduct a hypothesis test at the 1% level of significance to determine whether the means arestatistically the same.Step 1: State the null and alternative hypotheses.Ho:[1 – [2 =v VoHa: ₁₂0(So we will be performing a two-tailedThe differences of sample means are t-distributedand distribution standard deviation 10.3Question Help: Post to forumPart 2 of 4Step 2: Assuming the null hypothesis is true, determine the features of the distribution of thedifferences of sample means.Submit Part$4test.)%5Search or type URL✔with distribution mean 06MacBook ProPart 1 of 47✓8

Given that, An experiment is conducted and data are collected from 26 males and 20 females. The…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A newly hired basketball coach promised a high-paced attack that will put more points on the board than the team's previously tepid offense historically managed. After a few months, the team owner looks at the data to test the coach's claim. He takes a sample of 36 of the team's games under the new coach and finds that they scored an average of 101 points with a standard deviation of 6 points. Over the past 10 years, the team had averaged 99 points. What are the appropriate hypotheses to test the new coach's claim at the 1% significance level? Multiple Choice Hoμ=101, HA μ # 101 Hg u = 101, HA μ > 101
Community college instructors' salaries in one state are very low, so low that educators in that state regularly complain about their compensation. The national mean is $45,661, but instructors from Mississippi claim that the mean in their state is significantly lower. They survey a simple random sample of 61 colleges in the state and calculate a mean salary of $43,024 with a standard deviation of $13,132. Test the instructors' claim at the 0.05 level of significance. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
According to a recent study published by the American Statistics for Educators Journal, statistics students spend, on average, 80 minutes a week playing video games. A certain instructor of statistics at WCC believes that WCC students spend less than this amount of time playing video games per week. To test his belief, he randomly samples 31 students and finds the sample mean to be 72 minutes with a standard deviation of 35 minutes. At the 0.05 level of significance, is there evidence to suggest that WCC students spend less than 80 minutes a week, on average, playing video games? Use the p-value approach. Define the parameter we are testing and setup a hypothesis to test the see if the statistics instructor is correct: Calculate the test statistics for this hypothesis test. What is the p-value for this hypothesis test?
The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 38 recent CFAs with a mean salary of $138,000 and a standard deviation of $34,000. A sample of 80 MBAs results in a mean salary of $130,000 with a standard deviation of $46,000.a) Specify the hypotheses to test whether a CFA designation is more lucrative than an MBA.b) Calculate the value of the test statistic and the p-value. Do not assume that the population variances are equal.c) At the 5% significance level, is a CFA designation more lucrative than an MBA?
The Chartered Financial Analyst (CFA) designation is fast becoming a requirement for serious investment professionals. It is an attractive alternative to getting an MBA for students wanting a career in investment. A student of finance is curious to know if a CFA designation is a more lucrative option than an MBA. He collects data on 36 recent CFAS with a mean salary of $145,000 and a standard deviation of $36,000. A sample of 47 MBAS results in a mean salary of $135,000 with a standard deviation of $24,000. Assume that H, is the population mean for individuals with a CFA designation and u, is the population mean of individuals with MBAS. (You may find it useful to reference the appropriate table: z table or t table) a. Set up the hypotheses to test if a CFA designation is more lucrative than an MBA at the 10% significance level. O Họ: 41- H2 = 0; HA: H1 - H2# 0 O Ho: 1-4220; HA H1 - 4200 b-1. Calculate the value of the test statistic. Do not assume that the population variances are…
A sample of 22 account balances of a credit company showed a mean customer balance of $4,300, but the marketing manager claimed that the mean balance for the population was $4450. The marketing manager did NOT have the population standard deviation, but the sample standard deviation was found to be $400. Use the p-value approach to conduct a full hypothesis test(all steps) that can be used to determine whether the mean of all account balances is significantly different from $4440. Let α = .05.
A newly hired basketball coach promised a high- paced attack that will put more points on the board than the team's previously tepid offense historically managed. After a few months, the team owner looks at the data to test the coach's claim. He takes a sample of 36 of the team's games under the new coach and finds that they scored an average of 101 points with a standard deviation of 6 points. Over the past 10 years, the team had averaged 99 points. What is(are) the appropriate critical value(s) to test the new coach's claim at the 1% significance level? -2.438 -2.438 and 2.438 2.326 2.438
According to the Insurance Association in US, the average annual expenditure for automobile insurance is $605. Suppose that in a simple random sample of 80 residents of New York, for most recent year their average expenditure was $638.62 with the standard deviation of $106.05. Based on these data, examine whether the average annual insurance for motorists in New York might be different from that in national level. Using the 0.05 level of significance, what conclusion do you reach? Also, construct and interpret 95% confidence interval for the population mean. Is the hypothesized mean within the interval? Is this consistent with the findings of the hypothesis test conducted?
A technician compares repair costs for two types of microwave ovens (type I and type II). He believes that the repair cost for type I ovens is greater than the repair cost for type II ovens. A sample of 35 type I ovens has a mean repair cost of $80.39. The population standard deviation for the repair of type I ovens is known to be $24.63. A sample of 31 type II ovens has a mean repair cost of $73.47. The population standard deviation for the repair of type II ovens is known to be $10.42. Conduct a hypothesis test of the technician's claim at the 0.05 level of significance. Let i be the true mean repair cost for type I ovens and µz be the true mean repair cost for type II ovens. Step 1 of 5: State the null and alternative hypotheses for the test.
Are low-fat diets or low-carb diets more effective for weight loss? A sample of 78 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 15.0 pounds with a sample standard deviation of 7.77 pounds. A second sample of 74 subjects went on a low-fat diet. Their sample mean weight loss was 16.3 with a standard deviation of 6.10. Can you conclude that the mean weight loss differed between the two diets? Use the a = 0.01 level.

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