One of the basic assumptions in Greenwood-Williamson model is thatasperity summits have a constant radius. Consider that asperity summitshave variable radius and the radius (R) depends on the height of asperity(z) as given by: R(z)-Ro exp(-kz). With this, derive the expressions for loadand contact area for elastic-plastic contact of two Gaussian rough surfaces.

The Greenwood-Williamson model is a mathematical model used to describe the contact between two…

Answered: One of the basic assumptions in…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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3. EDL over an infinite cylinder: Consider a infinitely long cylinder of radius Ro. The cylinder is negatively charged at its surface. The cylinder is in contact with an symmetric electrolyte solution. Assuming axisymmetry and low potential (i.e. dimensionless y « 1), obtain a linear differential equation for the dimensionless potential. Solve the resulting dimensionless problem for the potential distribution. Hint: The governing equation can be modified to Bessel's equation.
When is weak form called variational form state the contition Please answer with respect to finite elemental method
Calculate ∝ for case (c)
H= 55mm A= 40mm R1 R2 B= 55mm C= 50mm R1=13mm H P=2000 N R2= 15mm A B Figure QI: A rectangular plate with holes
1 Normal Kuv ve xDE 12 Atalet Mom.ox O 13 Egilme.pdf C 14 Burulma pdf 2020-2021 620the%20solid%20circular%20section%20bar%20with%20radius%20R.pdf A Sesli oku In the solid circular section bar with radius R=10mm in the figure, due to the given loading, Find the cross-sectional effects at point A, Draw the normal stress distribution az on the section, Draw the shear stress distribution T on the section. 5. X m P = 12 kN Q = 1Y kN 2m X-7 Y=1 Z=0
A thin flexible gold chain of uniform linear density has a mass of 17.5 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale. Evaluate the magnitude of the force on the left hand pole. 30 28 26 24 22 20 18 16 14 12 10 8 6 4 2 0 0 2 4 6 58 10 12 14 16 18 20 22 24 26 28 30
2) Design a chain link (meaning find its diameter) made out of a ductile cast iron which needs to operate in a furnace that is used to fire ceramic bricks. The chain will be used for five years at 600°C with an applied load of 5000 lbs. Below is a diagram of the chain link and the Larson-Miller parameter graph for this particular cast iron. Be sure to use the specific equation for the Larson-Miller parameter provided on the x-axis of the graph. Furthermore, for your calculations assume a Safety Factor of 2. Stress (psi) 20,000 10,000 8,000 6,000 4,000 2,000 1,000 32 34 36 Larson-Miller parameter = 30 38 40 42 (36+0.78 ln 1) T(K) 1000 1200 dis SH ER
A circular plate is being supported by 7 outer springs and a central spring. The outer springs are equally placed around a bolt circle. Take note that the outer springs are 2 mm shorter than the central spring. Further, a 5000- Newton force is applied at the center of the plate pushing the springs down.
(b) A probe and an asteroid collide in space. A disc made of copper, of diameter 56 m and thickness 1.2 m at a temperature of 850°C, is dislodged from the probe and floats freely in space, rotating about its axis of symmetry with an angular speed w = 25 rad s-1. The disc radiates heat, and its temperature falls to 20°C. Assume that no external torque acts on the disc. Find: (i) the change in kinetic energy of the disc, given the disc radius shrinks by an amount Ar = (acuAT}r; for a temperature change AT, where r; is the initial radius and aeu = 1.67 × 10-5 °C-1; (ii) the change in internal energy of the disc; and (iii) the amount of energy radiated by the disc. Note: Moment of inertia of a disc of mass M and radius R, I = }M R? Density of copper, Pou = 8960 kg m-3 Specific heat capacity of copper, Ccu = 385 J (kg °C)-1
Consider a two degree of freedom bar elements as shown in figure. Using finite element method to formulate the equilibrium equation of it. If the cross sectional area is 12 mm? and E=200 GN/m?. 30KN 15KN 20KN 300+ 600 + 350 - All Dimension in mm
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H.W 1. Consider a two degree of freedom bar elements as shown in figure. Using finite element method to formulate the equilibrium equation of it. If the cross sectional area is 12 mm and E=200 GN/m². 20KN +30KN 15KN 300 * 600- + 350 All Dimension in mm 2. Consider a two degree of freedom bar element as shown in figure. Using finite element method to formulate the equilibrium equation of it, and then estimate the stress distributions. If Esteel-200 GN/m, Ecopper 110GN/m and EAL= 120 GN/m?. d=3 Steel AL Соpper 20KN - 30KN →15KN 300 * 200 - 400 * 350 All Dimension in mm

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