oduced from 67.3 g of C₂H6O3 a 5.0% yield from the reaction belo 7H6O3 (S) + C₂H6O3 (1)→ C9H3O4 C₂H3O₂ (aq).

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### Question

What mass (in grams) of aspirin (\(C_9H_8O_4\)) is produced from 67.3 g of \(C_7H_6O_3\) assuming 95.0% yield from the reaction below?

\[
C_7H_6O_3 (s) + C_4H_6O_3 (l) \rightarrow C_9H_8O_4 (s) + HC_2H_3O_2 (aq)
\]

### Explanation

In this question, we need to calculate the theoretical and actual mass of aspirin produced from the given starting material, \(C_7H_6O_3\) (salicylic acid), assuming a reaction yield of 95.0%.

### Steps to Solve

1. **Balanced Chemical Equation**: 
   \[
   C_7H_6O_3 (s) + C_4H_6O_3 (l) \rightarrow C_9H_8O_4 (s) + HC_2H_3O_2 (aq)
   \]

   Here, one mole of \(C_7H_6O_3\) reacts with one mole of \(C_4H_6O_3\) to produce one mole of \(C_9H_8O_4\) (aspirin) and one mole of acetate.

2. **Molar Mass Calculation**:
   - Molar mass of \(C_7H_6O_3\) (salicylic acid) = 138.12 g/mol
   - Molar mass of \(C_9H_8O_4\) (aspirin) = 180.16 g/mol

3. **Moles of Salicylic Acid**:
   \[
   \text{Moles of } C_7H_6O_3 = \frac{67.3 \, \text{g}}{138.12 \, \text{g/mol}} \approx 0.487 \text{ mol}
   \]

4. **Theoretical Yield of Aspirin**:
   \[
   \text{Theoretical moles of } C_9H_8O_4 = \text{Moles of } C_7H_6O_3 = 0.487 \
Transcribed Image Text:### Question What mass (in grams) of aspirin (\(C_9H_8O_4\)) is produced from 67.3 g of \(C_7H_6O_3\) assuming 95.0% yield from the reaction below? \[ C_7H_6O_3 (s) + C_4H_6O_3 (l) \rightarrow C_9H_8O_4 (s) + HC_2H_3O_2 (aq) \] ### Explanation In this question, we need to calculate the theoretical and actual mass of aspirin produced from the given starting material, \(C_7H_6O_3\) (salicylic acid), assuming a reaction yield of 95.0%. ### Steps to Solve 1. **Balanced Chemical Equation**: \[ C_7H_6O_3 (s) + C_4H_6O_3 (l) \rightarrow C_9H_8O_4 (s) + HC_2H_3O_2 (aq) \] Here, one mole of \(C_7H_6O_3\) reacts with one mole of \(C_4H_6O_3\) to produce one mole of \(C_9H_8O_4\) (aspirin) and one mole of acetate. 2. **Molar Mass Calculation**: - Molar mass of \(C_7H_6O_3\) (salicylic acid) = 138.12 g/mol - Molar mass of \(C_9H_8O_4\) (aspirin) = 180.16 g/mol 3. **Moles of Salicylic Acid**: \[ \text{Moles of } C_7H_6O_3 = \frac{67.3 \, \text{g}}{138.12 \, \text{g/mol}} \approx 0.487 \text{ mol} \] 4. **Theoretical Yield of Aspirin**: \[ \text{Theoretical moles of } C_9H_8O_4 = \text{Moles of } C_7H_6O_3 = 0.487 \
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