OD < 2 of 2 Part B As shown, a system of cables supports a bucket. (Figure 2) The dimensions in the figure are as follows: ₁ -5.25 ft, 2= 1.40 ft y = 2.20 ft. 3/2=4.50 ft. z₁ = 3.25 and 22 =2.30 ft. If the bucket and its contents have a combined weight of W = 11.5 lb, determine TA. To. and Tc. the tensions in cable segments DA, DB, and DC respectively. Express your answers numerically in pounds to three significant figures separated by commas. ▸ View Available Hint(s) TA TB TC Submit Provide IVE ΑΣΦ Previous Answers Part C Complete previous part(s) vec 1 X Incorrect; Try Again; 4 attempts remaining a C ? lb

OD < 2 of 2 Part B As shown, a system of cables supports a bucket. (Figure 2) The dimensions in the figure are as follows: ₁ -5.25 ft, 2= 1.40 ft y = 2.20 ft. 3/2=4.50 ft. z₁ = 3.25 and 22 =2.30 ft. If the bucket and its contents have a combined weight of W = 11.5 lb, determine TA. To. and Tc. the tensions in cable segments DA, DB, and DC respectively. Express your answers numerically in pounds to three significant figures separated by commas. ▸ View Available Hint(s) TA TB TC Submit Provide IVE ΑΣΦ Previous Answers Part C Complete previous part(s) vec 1 X Incorrect; Try Again; 4 attempts remaining a C ? lb

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

21
B
-32 C
D
Z2
<2 of 2
>
▼
Part B
As shown, a system of cables supports a bucket. (Figure 2) The dimensions in the figure are as follows: ₁ -5.25 ft, 2 = 1.40 ft. y₁=2.20 ft. 3/2=4.50 ft. 2₁ = 3.25
and 22 = 2.30 ft. If the bucket and its contents have a combined weight of W = 11.5 lb, determine TA. TB. and Tc. the tensions in cable segments DA, DB, and DC,
respectively.
Express your answers numerically in pounds to three significant figures separated by commas.
▸ View Available Hint(s)
TA TB.TC
Submit
175) ΑΣΦ | 41
Previous Answers
Provide Feedback
X Incorrect; Try Again; 4 attempts remaining.
Part C Complete previous part(s)
vec 6
0
BOA
?
lb

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