Consider the floor plan shown in the figure. Given: X=30 ft. -6 @ 6.67= B2 G3 BI GI Cz 83 2010-20 5@8-40° Compute the tributary area for floor beam B1 by simplified load distribution and actual load distribution. The tributary area (47) for floor beam B1 by simplified load distribution is The tributary area (47) for floor beam B1 by actual load distribution is

Question A1. The doubly reinforced rectangular concrete section shown in Figure A-1 is designed for the hogging moment of a continuous beam. The section has a total depth of D mm, width B= 300 mm and is reinforced with 4N28 bars at the top and 2N28 bars at the bottom. Given: f. = 40 MPa, fay = 500 MPa. Find other required data from AS3600-2018. a) Calculate the beam depth, D where D = 500+20n mm. Take n = 3rd digit of your student number. For example: your student number = 18505679, n = 5; D = (500+ 20*5)=600 mm) Note: Use the calculated D from (a) for the further calculation in (b-c). b) Calculate ultimate moment capacity (Mu) of the section. c) Check ductility of the section according to AS3600-2018. 300 4N28 2N28 Figure A-1

A column in the upper story of a building is subjected to a compressive load from the followingsources: dead load = 30.8 kips, occupancy live load = 1.7 kips, roof live load = 18.7 kips, and snowload = 19.7 kips.a. If load and resistance factor design (LRFD) is used, determine the factored load (requiredstrength) to be used in the design of the column. Which ASCE load combination controls?b. What is the required design strength of the column?c. What is the required nominal strength of the column for a resistance factor phi of0.9?d. If allowable strength design (ASD), determine the required load capacity (requiredstrength) to be used in the design of the column. Which ASCE load combination controls.e. What is the required nominal strength of the column for a safety factor Omega of 1.67.

Problem 2 4" For the problem below, 600 lb (1) Plot V&M diagram using graphic method (2) Calculate shear stress 300 Ib/ft Tm and tn at 8' from A (3) Plot shear stress B 200 lb/ft DA 8" 10' 5' distribution at 18' 6' 900 lb 1500 lb from A 1" Note: the uniformly distributed load 200 lb/ft is upwards and 300 Ib/ft is downwards 5600 ft-lb 3500 ft-lb