Obtain the value of the maximun bendling moment for the given beam. (Ay= 133.75 KN Az=0 B= 206.25 N) 40 kN,m 150 kN-m Sm 3 m

Q: 4. If the coefficient of static friction My-0.35, will the box move? 738lb 20 180lb

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Q: Compute the maximum bending moment of the given beam below. (kN-m)

A: Using trial and error to find zero shear positionFIND REACTIOIN AT B:∑MD=0…

Q: A reinforced concrete T-beam has an effective flange width of 750 mm with a thickness of 100 mm. The…

A: given- an isolated T beam. required- to find moment carrying capacity of T beam.

Q: Solve the slope and deflection of the simply- supported beam shown at D. Use Conjugate Beam Method.…

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Q: Consider the given beam below. Determine the following: 10 KN 11 KN 20 76° A + + 1m im 2m 11 KON 30…

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Q: Simply-supported beams with overhangs 10 m 40 kNm B +4 10 m 800 R q=5 kN/m 8 m D

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Q: Determine the force and moment reactions at the support A of the cantilever beam subjected to the…

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Q: 2. Replace the loading by an equivalent resultant force and specify its location on the beam,…

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Q: PB= 30 kN 4 m 3 m 3 m E A B D Cp= 40 kN • m

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Q: Q:by using influence lines.findshear and moment in point h.

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Q: What is the moment MBC and MABin KN-m? 2 decimal places

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Q: If the distance between E and Bis h= 0.3 m, calculate the maximum absolute values of the shear and…

A: Given Data  Find maximum absolute shear force and bending moment.

Q: A В D a

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Q: 25 kN 8 kN/m 10 kN-m 2 m A 15 kN 30° 12 kN 2.5 m 1 m 3 m 2.5 m 2 m

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Q: What is the Maximum moment in kN-m. Given: w1 = 42, w2 = 11, a = %3D 3, b = 4, and c = 3. w1 kN/m w2…

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Q: Solve using the Force Method via primary and flexibility/virtual structures. Use point C as…

A: Determination of reaction using force method

Q: rmine the end-moments for the continuous beam below. EI is constan

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Q: Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P2 = 35 kN, and…

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Q: the mobile crane (weight =48 kN) moves across the brige of length, l =14m. the front wheels of the…

A: Draw the free-body diagram of the bridge. Let the resultant load is acting as shown in the…

Q: What is the fixed end moment FEMAB for the beam with a settlement of 25 mm at support C? 20 kN/m 60…

A: Given data in question  UDL Span member length  Settlement  To find out  Fixed end moment of AB

Q: 1. For the restrained beam shown below, compute the end moments (kN-m). 1 m 3 kN-m 1 m 1. What is M…

A: we will use slope deflection method to determine the Moment at the ends

Q: 18. For the beam shown in figure 9, solve for the fixed end moment (FEM) at joint B in kN-m. Use a =…

A: Given data in question  Point load UVL Span member length  To find out  Fixed end moment at joint B

Q: 69 KN/m 41 KN В C D А L= 1.5 m L= 2.2 m L= 3.6 m RD RB

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Q: (a) Replace the loading acting on the beam by an equivalent resultant force FR and couple moment…

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Q: A reinforced concrete beam has a width of 300mm and a overall depth of 500mm. The beam is simply…

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Q: Q3: Draw the shear force and bending moment diagrams for the beam.

A: Solution Draw the Diagram

Q: Question #2 Neglect the thickness of the beam. Determine the total moment of the forces: i) about…

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Q: Question 6 E F D 225 kN 6 m A B 6 m 6 m Using Cantilever Method, determine the Shear force at EF in…

A: Given data in question  Frame Load Dimension To find out  Shear force in EF

Q: PDL = 5 KN 500 mm Wp =6 KN/m WL =3 KN/m PLL = 3 KN 800 mm RI R: 2 m 1m 1 m

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Q: SLOPE

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Q: or the frame shown, the Moment Distribut )to draw the shear and bending moment ettlement of 0.25…

A: In the above question, a frame is given with all information we need to determine the following…

Q: 69 KN/m 41 KN B C D А L= 1.5 m L= 2.2 m L= 3.6 m RD RB

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Q: Calculate the maximum shear stress in the beam shown (in N/mm) if it is of rectangular cross-sectión…

A: Given data : Width (b)=107 mmDepth (d)=187 mmTo find :Maximum shear stress

Q: What is the Maximum moment in kN-m. Given: w = 45, a = 3, b = 2, and c = 3. %3D w kN/m *cm> Rp am bm…

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Q: A rectangular reinforced concrete beam has a width of 350mm and an effective depth of 650mm. The…

A: Given Data Width of beam (b) = 350 mm  Effective depth of beam (d) = 650 mm  fc' = 20.7 MPa  fy =…

Q: Solve for the angle at the hinge support and the deflection at point C. El= 20000KN-m2. Use…

A: Given,  There is a  simply supported beam given in the question..  The total length of the beam =…

Q: For the beam loaded as shown in the figure below, determine the following unknov method. а. Moment…

A: Solution:MA1=-wl212=24.3×8212=-129.6 kN.mMC1=wl212=24.3×8212=129.6 kN.m As per the given Figure:

Q: Consider the given figure. Given: P = 29 kN. 24 KN PKN 8 KN 8m 3m 24 m B Determine the maximum value…

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Q: 4. Fixed-end moment (FEM) on joint C of member CD in kN-m, FEMCD Choices: 27.556 9.587 16.185…

A: Fix end moment for CD MFCD = -wa2(3a2 -8al + 6l2)/12l2    w = 15kn/m a = 3m l = 5m MFCD = -…

Q: Problem 1: For the shown beam: a. Calculate the Equivalent Concentrated force FR for the 5 KN 4.0…

A: We are authorized to answer one question and three subparts at a time since you have not mentioned…

Q: 7 kN-m E 3m 0.90 0.90 KN NYL C 2.4 KN 2m D 3 m. 1.3 kN 1m

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Q: Determine the magnitude of the maximum bending moment in AC. Answer in kN-m rounded-off to 2 decimal…

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Q: For the given beam section, solve all the unknown support reactions. Also, using EI=20,000 N-m2,…

A: Reactions will be determined after performing three-moment theorem.

Q: Identity the maximum shear and maximum moment.

A: Taking BC part to find the reaction at B and it will be the load act in the beam AB at B. ∑MC=0RB×2…

Q: 43 kN/m -4 m 29 kN/m 8m 4m 133. KN 81. kN - m

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System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.