O. The velocity of a particle undergoing simple harmonic motion is described by, v(t) = 2.25 [m/s] cos(0.555 [rad/s] t +0.450 [rad]) . What is the particle's maximum acceleration?

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter16: Oscillations
Section: Chapter Questions
Problem 8PQ: The expression x = 8.50 cos (2.40 t + /2) describes the position of an object as a function of time,...
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30. The velocity of a particle undergoing simple harmonic motion is described by,
v(t) = 2.25 [m/s] cos(0.555 [rad/s] t +0.450 [rad])
What is the particle's maximum acceleration?
A. 1.01 [m/s²]
C. 1.25 [m/s²]
B. 1.12 [m/s²]
D. 2.25 [m/s²]
Transcribed Image Text:30. The velocity of a particle undergoing simple harmonic motion is described by, v(t) = 2.25 [m/s] cos(0.555 [rad/s] t +0.450 [rad]) What is the particle's maximum acceleration? A. 1.01 [m/s²] C. 1.25 [m/s²] B. 1.12 [m/s²] D. 2.25 [m/s²]
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