ны Санз стог w/solu W solvent CDC3 16 15 14 13 12 11 10 9 8 -7.240 7 6 f1 (ppm) 5 -4.132 F-00'2 4 3 2 -0.014 -0.023 -0.031 0 -1 -2 -3 -4 -2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -1E+05 -1E+05 -1E+05 -1E+05 -1E+05 -90000 -80000 -70000 -60000 -50000 -40000 -30000 -20000 -10000 FO --10000 --20000

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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C2H3ClOis the formula, the solvent is CDCl3. Need help determining Integration values the multiplicity and the chemical the Peak refers to.

 

Adinden
слог
#31 C2H3 C10₂
w/ solvent CDC1₂
16
15
14
13
12
11
10
CO.
9
8
-7.240
7
6
f1 (ppm)
-5
-4.132
F-00'7
4
3
2
--0.014
-0.023
--0.031
0
- 1
-2
-3 -4
-2E+05
-2E+05
-2E+05
-2E+05
+2E+05
-2E+05
-2E+05
-2E+05
-2E+05
-1E+05
-1E+05
-1E+05
-1E+05
-1E+05
-90000
-80000
-70000
-60000
-50000
-40000
-30000
-20000
-10000
-0
--10000
--20000
Transcribed Image Text:Adinden слог #31 C2H3 C10₂ w/ solvent CDC1₂ 16 15 14 13 12 11 10 CO. 9 8 -7.240 7 6 f1 (ppm) -5 -4.132 F-00'7 4 3 2 --0.014 -0.023 --0.031 0 - 1 -2 -3 -4 -2E+05 -2E+05 -2E+05 -2E+05 +2E+05 -2E+05 -2E+05 -2E+05 -2E+05 -1E+05 -1E+05 -1E+05 -1E+05 -1E+05 -90000 -80000 -70000 -60000 -50000 -40000 -30000 -20000 -10000 -0 --10000 --20000
.165
4.160
4.155 4.150 4.145
4.140
4.132
2.00-
4.135 4.130
f1 (ppm)
4.125 4.120
4.115
4.110 4.105
4.100 4.095
4.090
-2E+05
-2E+05
-2E+05
-2E+05
+2E+05
-2E+05
-2E+05
+2E+05
-2E+05
-1E+05
-1E+05
-1E+05
-1E+05
-1E+05
-90000
-80000
-70000
-60000
-50000
--40000
-30000
-20000
-10000
-O
-- 10000
--20000
Transcribed Image Text:.165 4.160 4.155 4.150 4.145 4.140 4.132 2.00- 4.135 4.130 f1 (ppm) 4.125 4.120 4.115 4.110 4.105 4.100 4.095 4.090 -2E+05 -2E+05 -2E+05 -2E+05 +2E+05 -2E+05 -2E+05 +2E+05 -2E+05 -1E+05 -1E+05 -1E+05 -1E+05 -1E+05 -90000 -80000 -70000 -60000 -50000 --40000 -30000 -20000 -10000 -O -- 10000 --20000
Expert Solution
Step 1

The n+1 rule, where n is the number of nearby spin-coupled nuclei with the same (or very similar) Js, can be used to predict the splitting pattern of a given nucleus (or set of equivalent nuclei).

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