Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 11000101 = X0X1X2X3X4X5X6X7 when encrypted by the LFSR produced the ciphertext 10010000 = yoYı Y2 Y3 Y3 Y5 Y6 Y7 · What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, p2 = 1, p1 = 0, po = 1). %3D

Database System Concepts
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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Chapter1: Introduction
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Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl.
We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of
states is m =
4.
The plaintext given by
11000101 — ХоXјX2XҙХ4X5X6X7
when encrypted by the LFSR produced the ciphertext
10010000
Уo У1 У2 Уз Уз У5 У6 Ут .
What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent
P3 = 0, p2 = 1, p1 = 0, po = 1).
Transcribed Image Text:Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 11000101 — ХоXјX2XҙХ4X5X6X7 when encrypted by the LFSR produced the ciphertext 10010000 Уo У1 У2 Уз Уз У5 У6 Ут . What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent P3 = 0, p2 = 1, p1 = 0, po = 1).
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