Nine spheres, each with a mass of 3.2 kg, are distributed evenly along a semicircle of radius r = 2.8 meters, as shown in the diagram above. The diameter of each sphere is much smaller than the radius of the semicircle. For purposes of a coordinate system, the center of the semicircle is at the origin of our coordinate system, and the entire semicircle is in the first and second quadrants (x coordinates range from -r to r meters, while y coordinates range from 0 to r meters. Find the location of the y coordinate (in meters) of the center of mass of the nine spheres.

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Chapter1: Units, Trigonometry. And Vectors
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Nine spheres, each with a mass of 3.2 kg, are distributed evenly along a semicircle of radius r = 2.8 meters, as shown in the diagram above. The diameter of each sphere is much smaller than the radius of the semicircle. For purposes of a coordinate system, the center of the semicircle is at the origin of our coordinate system, and the entire semicircle is in the first and second quadrants (x coordinates range from -r to r meters, while y coordinates range from 0 to r meters.

Find the location of the y coordinate (in meters) of the center of mass of the nine spheres.

X = 0
y = r
X = -r
y = 0
x = r
y = 0
Transcribed Image Text:X = 0 y = r X = -r y = 0 x = r y = 0
Expert Solution
Step 1

The centre of semicircle is at the origin of our coordinate system

                                   θ = 904 =22.5

Radius of semicircle (r) =2.8 metre is given.

                y= 0

                y1rsinθ = 2.8 sin (22.5) = 1.0715

                y2 = rsinθ = 2.8 sin ( 2 x 22.5) = 1.98

                y3 = rsinθ = 2.8 sin (3 x 22.5) = 2.58

                y = r = 2.8 (given)

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