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Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 35 individuals. The average time that the 35 people spent reading the paper was 12.2 minutes. At α=0.10, is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the
(a) State the hypothesis and identify the claim with the correct hypothesis.
:H0 ▼(Choose one) claim/not claim
:H1 ▼(Choose one) claim/not claim This hypothesis test is a ▼(Choose one) one tailed/two talied test. (b)Find the critical value(s). Round the answer to 2
decimal places, if necessary. |
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z=
▼(Choose one) reject/do not reject the null hypothesis.
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There ▼(Choose one) enough evidence to support the claim that there is a change in the average time an individual spends reading the newspaper.
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Find the 90% confidence interval of the mean. Round the answers to nearest whole number.
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▼(Choose one) , since the confidence interval does not contain the hypothesized mean of 10.8 minutes, it ▼(Choose one) support the rejection of the null hypothesis and the answer from part 5. |
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