new system that has a first cost of $212,400, annual operating and maintenance costs of $41,200, annual savings of $94,600, a life of 6 years, and a salvage value of $32,500. After initial evaluation, the firm receives word from the vendor that the first cost is 5% higher than originally quoted. The percentage error in the system' s present worth from this is closest to what

new system that has a first cost of $212,400, annual operating and maintenance costs of $41,200, annual savings of $94,600, a life of 6 years, and a salvage value of $32,500. After initial evaluation, the firm receives word from the vendor that the first cost is 5% higher than originally quoted. The percentage error in the system' s present worth from this is closest to what

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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The engineer of a medium scale industry was instructed to prepare at least two plans which is to be considered by management for the improvement of their operations. Plan "A" calls for an initial investment of P200,000 now with a prospective salvage value of 20% of the first cost 20 years hence. The operation and maintenance disbursement are estimated to be P15,000 a year and taxes will be 2% of first cost. Plan "B" calls for an immediate investment of P140,000 and a second investment of 160,000 eight years later. the operation and maintenance disbursements will be P9,000 a year for initial installation and P8,000 a year for the second installation. At the end of 20 years the salvage value shall be 20% of the investments. Taxes will be 2% of the first cost. If money is worth 12%, which plan would you recommend? Solve using present worth cost method and equivalent uniform annual cost method.
GeoWorld Systems uses a subset of the following questions during the interview process for new engineers. For each of the following cases, determine if “the project” or “do nothing” is preferred. The value of MARR in each case is 14%.
Factor Company is planning to add a new product to its line. To manufacture this product, the company needs to buy a new machine at a $495,000 cost with an expected four-year life and a $10,000 salvage value. Additional annual information for this new product line follows. (PV of $1, FV of $1, PVA of $1, and FVA of $1) Note: Use appropriate factor(s) from the tables provided. Sales of new product Expenses Materials, labor, and overhead (except depreciation) Depreciation-Machinery Selling, general, and administrative expenses Required: 1. Determine income and net cash flow for each year of this machine's life. $ 1,960,000 1,502,000 121,250 167,000 2. Compute this machine's payback period, assuming that cash flows occur evenly throughout each year. 3. Compute net present value for this machine using a discount rate of 8%. Complete this question by entering your answers in the tabs below. Required 1 Required 2 Required 3 Determine income and net cash flow for each year of this machine's…
An interest rate of 15% is used to evaluate a new system that has a first cost of $212,400, annual operating and maintenance costs of $41,200, annual savings of $94,600, a life of 6 years, and a salvage value of $32,500. After initial evaluation, the firm receives word from the vendor that the first cost is 5% higher than originally quoted. The percentage error in the system’s present worth from this is closest to what value? (a) 5% (b) 15% (c) 100% (d) 300%
Compare two alternatives, 1 and 2, on the basis of a present worth evaluation using 10% per year and a study period of 8 years. Alternative First Cost Annual Operating Cost Overhaul in Year 4 Salvage Value Life Answer to the nearest whole dollars for currency, and the nearest percentage (no decimals) for interest, and a whole number for the number of years. Do NOT enter commas. DO enter minus signs for negative values. 1) What is the Present Worth of Project 1? $ 1 2 ($13,000) ($49,000) ($6,000) ($5,000) $0 ($3,350) $1,800 $6,800 4 years 8 years
An engineer proposes to spend $95,000 on a capital project to upgrade a package delivery system. The project is expected to have labor savings of $20,000 a year plus reduce scrap costs by $5000 a year. There is expected to be no salvage value at the end of the equipment life, which is anticipated to be 7 years. MARR is 12%. This question is in five parts. The engineer next performs a sensitivity analysis for a best case and worst case scenario: Best Case Worst Case Initial Cost $95,000 $110,000 Labor Savings $25,000 $15,000 Scrap Cost Reduction $6,000 $4,00O Part 4: What is the present worth (PW) in the worst case scenario? (your answer should be a positive or negative number and do not use commas or $ signs)
The Reiph Transportation Company is planning to buy a new fleet of trucks requiring an initial investment of $1,000,000, and $2,500,000 annually to maintain and operate. The expected life of the new fleet is 10 years. The revenue is estimated to be $5,000,000 per year and the salvage value is expected to be $250,000. The MARR is 18%. Conduct a sensitivity analysis based on the given information. a. Calculate the PW of the Base case based on above given data. (Do not use AW or FW) b. Calculate the PW for the range of -10% to +15% for initial cost. (Do not use AW or FW)
The production department is proposing the purchase ONE automatic insertion machine. It has identified three machines (A, B and C). Each machine has an estimated useful life of 10 years. minimum desired rate of return of 10%. The accountant has identified the following data: Machine A Machine B Machine C Present value of future cash flows computed using 10% rate of return $305,000 $295,000 $300,500 Amount of initial investment 300,000 300,000 300,000 Based on net present value method, which machine do you recommend?
if a company is considering buying a system that costs 450,000 with an estimated 10-year life and a salvage value of 70,000, the estimated operating results with the new machine are, incremental revenue = 180,000, incremental expenses = 123,000 which is made up by, expenses other than depreciation = 85,000, depreciation (straight-line basis) = 38,000, and incremental income = 57,000, and all revenue and expenses other than depreciation use cash, how do I find the annual net cash flow, time of the payback period, return on investment percentage, and the Net present value, discounted at an annual rate of 6% (present value of $1 due in 10 years, discounted at 6%, is 0.558; present value of $1 received annually for 10 years, discounted at 6%, is 7.360)?
DuraTech Manufacturing is evaluating a process improvement project. The estimated receipts and disbursements associated with the project are shown below. MARR is 6%/year. Solve, a.What is the future worth of this investment?b. What is the decision rule for judging the attractiveness of investments based on future worth? c. Should DuraTech implement the proposed process improvement?
Factor Company is planning to add a new product to its line. To manufacture this product, the company needs to buy a new machine at a $491,000 cost with an expected four-year life and a $20,000 salvage value. Additional annual information for this new product line follows. (PV of $1. EV of $1. PVA of $1, and EVA of $1) (Use appropriate factor(s) from the tables provided.) Sales of new product Expenses Materials, labor, and overhead (except depreciation) Depreciation-Machinery Selling, general, and administrative expenses Required: 1. Determine income and net cash flow for each year of this machine's life. 2. Compute this machine's payback period, assuming that cash flows occur evenly throughout each year. 3. Compute net present value for this machine using a discount rate of 7%. $ 1,990,000 1,509,000 117,750 162,000 Answer is complete but not entirely correct. Complete this question by entering your answers in the tabs below. Required 1 Required 2 Required 3 Compute net present value…
1. Determine the NPV of the new computer system (use 3 decimal places for the PV factor)

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