MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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NebNas manages the credit department for a grocery store chain in the province, and she would like to determine whether the
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- A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 88.1. He knows the population standard deviation for the evening classes to be 4.2 points. A random sample of 150 students from morning classes results in a mean test score of 89.1. He knows the population standard deviation for the morning classes to be 7.7 points. Test his claim with a 95 % level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.arrow_forwardYou are applying for a job at two companies. Company A offers starting salaries with u = $33,000 and o = $1,000. Company B offers starting salaries with u = $33,000 and o = $3,000. From which company are you more likely to get an offer of $35,000 or more? Choose the correct answer below. O A. Company A, because data values that lie more than two standard deviations from the mean are considered unusual. O B. No difference, because data values that lie more than three standard deviations from the mean are considered very unusual. O C. Company B, because data values that lie within one standard deviation from the mean are not considered unusual.arrow_forwardAccording to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches. If Zsike is 67 inches tall, what is her z-score?arrow_forward
- One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GILarrow_forwardA hospital president claims that the average Salary of registered nurses at her hospital is more than $57,000. You test this claim by surveying 37 registered nurses at this hospital and find they have a mean salary of $57,425. Assume the population standard deviation is $1750 at the 0.10 level of significance is there enough evidence to support the claim of the hospital president?arrow_forwardA professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 76.8. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 77.8. He knows the population standard deviation for the morning classes to be 1.9 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1__μ2arrow_forward
- A survey found that the mean commute time is 25.4 minutes for the fifteen largest U.S. cities.The Austin, TX, chamber of commerce feels that Austin's commute time is less. A survey of 25 randomly selected commuters had a mean of 22.1 minutes with a standard deviation of 5.3 minutes. At the 10% level, does the survey data suggest that Austin commute time is significantly less than the national average? Your answer should have the following: 1). Null hypothesis:2). Alternative hypothesis: 3). Test Type: P-testarrow_forwardRussell is doing some research before buying his first house. He is looking at two different areas of the city, and he wants to know if there is a significant difference between the mean prices of homes in the two areas. For the 39 homes he samples in the first area, the mean home price is $176,400. Public records indicate that home prices in the first area have a population standard deviation of $32,930. For the 32 homes he samples in the second area, the mean home price is $181,500. Again, public records show that home prices in the second area have a population standard deviation of $23,835. Let Population 1 be homes in the first area and Population 2 be homes in the second area. Construct a 95% confidence interval for the true difference between the mean home prices in the two areas. Round the endpoints of the interval to the nearest whole number, if necessary. Lowest Endpoint = upper Endpoint=arrow_forwardThe manager of a major retail store has taken a random sample of 25 customers. The average sale was $52.50. The population standard deviation is known to be $6.10. The manager would like to determine whether or not the mean sales by all customers are significantly more than $50. What is the p-value for the test?arrow_forward
- According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 64 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. (a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for # as needed.) Ho: H: (b) Using the sample from the 64 bottles, what is the test statistic? (Round your answer to three decimal places.) Using the sample from the 64 bottles, what is the p-value? (Round your answer to four decimal places.) p-value =…arrow_forwardJohn finds that there is a scholarship available to all persons scoring in the top 5 % on the ACT test. If the mean score on the ACT is 21 with a standard deviation of 4.7, what score does he need in order to qualify for the scholarship?arrow_forwardMiranda and Karla began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Miranda took a test in Social Studies and earned a 71.4, and Karla took a test in Art History and earned a 60.9. Use the fact that all the students' test grades in the Social Studies class had a mean of 75.3 and a standard deviation of 10.7, and all the students' test grades in Art History had a mean of 66.4 and a standard deviation of 10.3 to answer the following questions.a) Calculate the z-score for Miranda's test grade.z=b) Calculate the z-score for Karla's test grade.z=c) Which person did relatively better? Miranda Karla They did equally well.arrow_forward
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