n equal tangent vertical curve is intended to connect grades of 1.8% and -2.7%. If this curve is to be a part of a highway designed with a speed limit of 40mph, determine the minimum length (ft) of the vertical curve. Use exact solution (do not use the table).

An equal-tangent equal tangent vertical curve connects a +2.10% initial grade and -2.70% final grade. The PVT is at station 127+18 and elevation 206.52 ft. If the design speed is 75 mi/h, what is the elevation of the curve at station 121+58? You answer must be in ft and rounded to the second digit, if you need to use values from tables, use "design" values (usually last column), not "calculated".

An equal-tangent crest vertical curve is 1100 ft long and connects a +2.5% and a -1.5% grade. If the design speed of the roadway is 85 mi/h, determine the length of curve, does this curve have adequate passing sight distance?

PERSONALIZE PLEASE: Can you show me the most detailed solution possible for this problem?  THE ANSWER IS M =4.0 m