Answered: n = 3 -0.85 eV --1.51 eV n =2 -3.4 eV…

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n = 3 -0.85 eV --1.51 eV n =2 -3.4 eV --13.6 eV

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter9: Condensed Matter Physics

Section: Chapter Questions

Problem 62P: Compare the density of states at 2.5 eV and 0.25 eV.

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Concept explainers

Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

Question

QUESTION 10

Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10^-15 eVs and c = 3.00 x 10⁸ m/s.

	a.	hc/1.89
	b.	1.89 x h x c
	c.	1.89/hxc
	d.	(1.51 + 3.4)/hc
	e.	hc/3.4

n = 3
-0.85 eV
--1.51 eV
n =2
-3.4 eV
--13.6 eV

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