n = 1.60 n = 1.40 n = 1.20 n = 1.00 Figure P34.45

Light rays in a material with index of refrection 1.39 can undergo total internal reflection when they strike the interface with another material at a critical angle of incidence. Find the second material's index of refraction n when the required critical angle is 73.3°. n =

A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction?   Calculate to 1decimal.

Consider a layer of Oil, Glass, and Air where the oil/glass boundary is parallel to the glass/air boundary. Let the index of refraction for the glass be 1.48 and the index of refraction for the oil to be 1.25. At what angle relative to the normal should a ray of light be directed upon the oil/glass interface such that it strikes the glass/air interface at the critical angle?

A ray of light is incident on an air/water interface. The ray makes an angle of θ1 = 29 degrees with respect to the normal of the surface. The index of the air is n1 = 1 while water is n2 = 1.33. Write an expression for the reflection angle ψ, with respect to the surface.

An engineer is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, she aims a narrow beam of light at a sample of this material, which has a smooth surface. She then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 59.5°. (a)What index of refraction describes the material? n =  (b)If some of the incident light (at ?i = 59.5°) enters the material and travels below the surface, what is the angle of refraction (in degrees)?