
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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During the intermediate step of solar nuclear fusion
a. 1 deuterium fuse with 1 proton making helium-3
b. 2 protons fuse together making helium-3
c. 2 deuterium nuclei fuse together making helium-3
d. 1 deuterium fuse with 1 proton making helium-4
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- 6.) A very old specimen of wood contained 10¹2 atoms of 14 C in 1986. (a) How many 14C atoms did it contain in the year 9474 B.C.2 (b) How many 14C atoms did it contain in 1986 B.C.?arrow_forwardHelp.arrow_forwardMultiple Choice Condition for solar nuclear fusion to take place a. Extremely hot temperature and gravity b.Extremely hot temperature and density c. Extremely hot temperature and large volume d. Extremely hot temperature and kinetic energy e. Extremely large energy and velocity, E = mC2arrow_forward
- 6. If Nitrogen-14 absorbs an alpha particle and then emits a Hydrogen-1, what is the resulting nucleus? 7. If Au-185 emits an alpha particle, what is the nucleus formed? 8. What nucleus emits an alpha particle and forms Th-234?arrow_forward6. The binding energy is the work that must be done to allow an object to escape to infinity. What is the binding energy for an object: a) on the surface of the earth b) in a circular orbit around the eartharrow_forwardPart 1: Carbon dating An archaeologist finds some ancient jewelry made from bone. The jewelry has a carbon mass of 387 g (HINT: Assume all the carbon is 12C and determine the number of atoms, 12C has a molar mass of 12 g/mol) and careful measurements show that the remaining 14C has a current decay rate of 20 decays/s. Determine the age of the bone (and presumably the jewelry). The ratio of 14C to 12C when the animal died was 1.25x10-12 & the half-life of 14C is 5730 y. Additionally, 1 mol = 6.022×1023 particles, 1 y = 365.25 days, & 1 day = 24 h. age of bone = Part 2: Rubidium-Strontium dating A geologist finds an old rock and wants to determine its age using rubidium-strontium dating. This is possible because 87Rb, which has a half-life of 4.75×1010 y, undergoes - decay and becomes 87Sr. The geologist determines that the ratio of 87 Sr to 87Rb is 0.033. Assuming there was no 87Sr in the rock when it was formed, determine the age of the rock. age of rock =arrow_forward
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