College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 31.0% of its original volume and the temperature is increased to 48.0°C. (a) What is the tire pressure in pascals?(b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. What is the new tire pressure (absolute) in pascals?arrow_forwardYou pour 998.00 cm3 of liquid mercury into a 1000.00 cm3-flask when both the mercury and the glass are at 4.0 ◦C. Determine the maximum temperature you can heat the system to (to the thousandth of a degree Celsius) before the mercury overflows. The mercury has a coefficient of volume expansion of 18.0 × 10−5◦C^−1 and the glass of the flask has a coefficient of volume expansion of 1.8 × 10−5◦C^ −1.arrow_forwardAn automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 27.0% of its original volume and the temperature is increased to 39.0°C. (a) What is the tire pressure in pascals? Pa (b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. What is the new tire pressure (absolute) in pascals? Paarrow_forward
- Step 1 (a) The ideal-gas equation describes each condition of the air in the tire. We will set up ratios in order to describe these changes. Dividing the equations PV = nRT in the initial and final states, we have PfVf Tf P¡Vi Ti Solving for the final pressure in the tire, gives Pf = = = which gives I Tf P(V)() P₁ Vf T₁ = (1.013 x 105 Pa) x 105 Pa. Note that the volume V¡ cancels out of the equation. = Vf Po = Pr (V ( ) ( ) Pd Pf Vi V₁ Step 2 (b) After the car is driven, the temperature and volume of air in the tire have changed. Let Td be the temperature and Vd be the volume of air in the tire. We have PdVd Td PfVf Tf' x 105 Pa 273 + 273 + Vf Vf Again we see that the volume Vf cancels out of the equation. °C K °℃ K = x 105 Pa.arrow_forwardA rod made of glass has a circular cross section with a diameter of 0.1200 m at a temperature of 20 degrees celsius. An aluminum ring has a diameter of 0.1196 m at a temperature of 20 degrees celsius. The coefficients of thermal expansion for glass and aluminum are 9.0 x 10-6 1/K and 24.0 x 10-6 1/K, respectively. At what temperature will the aluminum ring be able to slip over the glass rod? Between 225 and 250 degrees celsius Between 175 and 200 degrees celsius Between 100 and 125 degrees celsius Higher than 300 degrees celsius Between 250 and 275 degrees celsius Between 125 and 150 degrees celsius Between 275 and 300 degrees celsius Between 150 and 200 degrees celsius O Between 200 and 225 degrees celsiusarrow_forwardA hot air balloon uses the principle of buoyancy to create lift. By making the air inside the balloon less dense then the surrounding air, the balloon is able to lift objects many times its own weight. A large hot air balloon has a maximum balloon volume of 2090 m3. a. If the air temperature in the balloon is 54 °C, how much additional mass, in kilograms, can the balloon lift? Assume the molar mass of air is 28.97 g/mol, the air density is 1.20 kg/m3, and the air pressure is 1 atm.arrow_forward
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